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scoray [572]
3 years ago
8

The quadratic 8x^2+12x-14 has two real roots. What is the sum of the squares of these roots? Express your answer as a common fra

ction in lowest terms.
Mathematics
2 answers:
leonid [27]3 years ago
8 0

Answer:

23/4

Step-by-step explanation:

s2008m [1.1K]3 years ago
8 0

Answer: 23/4

Step-by-step explanation:

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_(9)=(2(1-2(2)^(9)))/(1-2(2))<br><br><br>PLEASE HELP ME OUT.
USPshnik [31]

Answer:

the answer = um ok

Step-by-step explanation:

4 0
3 years ago
find the length of the long diagonal of a rhombus when it's area of 24 square centimeters and it's short diagonal is 4 centimete
Ivahew [28]

Answer:

12

Step-by-step explanation:

A rhombus is a parallelogram with all four sides equal.

Its diagonals are perpendicular.

Each of the triangles formed by the diagonals and the sides are congruent, so the area of the rhombus is 4 times the area of one of the triangles.

Since the short diagonal is given as 4, each of the triangles can be viewed as having a base of 2.  Each triangle's height, h, then is one half the length of the long diagonal.

The are of one of the triangles is 1/2 (base)(height)=(1/2)(2)h

The area of the rhombus is then

4(1/2)(2)h=24

Solving for h gives

h=6

This makes the length of the long diagonal 2h=12

6 0
3 years ago
Write the sum as a product of two factors: 12a + 16b + 8
serious [3.7K]
Answer - 20a + 24b because 8 is added to both variables.
5 0
3 years ago
Read 2 more answers
Elliaarteaga14
ozzi

Answer:20 gallons

Step-by-step explanation:

6 0
2 years ago
Solve equation for X<br> c(x-3)-4=b(x+7)
Alenkasestr [34]
Answer:

c(x-3)-4=b(x+7)
(cx-c•3)-4=b(x+7)
cx-3c-4=b(x+7)
cx-3c-4=bx+b•7
-3c-7b-4=bx-cx
x(b-c)=-3c-7b-4
x(b-c)/b-c = -3c-7b-4/b-c

x=-3c+7b+4/b-c
3 0
3 years ago
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