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3 years ago

9

Olivia orders 24 cupcakes and a layer cake. The layer cake costs $16, and the total cost of the order is $52. What is the cost o

f each cupcake?

2 answers:

exis [7]3 years ago

5 0

Answer:

The total cost was $52. Subtracting out the cost of the layer cake ($16) leaves us with $36 to pay for the 24 cupcakes. This means that each cupcake must have cost $1.50 ( = $36 / 24 cupcakes ).

Step-by-step explanation:

mixas84 [53]3 years ago

4 0

Answer:

Below

Step-by-step explanation:

First let us create an equation for this problem

(24 cupcakes)( $ of each cupcake) + ( $16 layer cake ) = $52

Let's say that C will represent the $ of each cupcake to make it easier

Solving it....

24C + 16 = 52

24C = 36

Divide both sides by 24

C = 1.5

Therefore, each cupcake cost $1.5

We can check to see if this works....

24(1.5) + 16 = total cost

36 + 16 = 52, so this is correct

Hope that helped! Best of luck <3

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Answer:

A. [1,10]

Step-by-step explanation:

Given

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Required

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The rate of change over [a,b] is calculated as:

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$Rate = \frac{N(10)-N(1)}{10 - 1}$

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$N(1) = 100e^{-0.023*1} = 100e^{-0.023} = 97.73$

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$Rate = \frac{N(20)-N(10)}{20 - 10}$

$Rate = \frac{N(20)-N(10)}{10}$

Calculate N(20) and N(10)

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$N(10) = 100e^{-0.023*10} = 100e^{-0.23} = 79.45$

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C. [15,25]

$Rate = \frac{N(25)-N(15)}{25 - 15}$

$Rate = \frac{N(25)-N(15)}{20}$

Calculate N(25) and N(15)

$N(25) = 100e^{-0.023*25} = 100e^{-0.575} = 56.27$

$N(15) = 100e^{-0.023*15} = 100e^{-0.345} = 70.82$

So:

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D. [1,30]

$Rate = \frac{N(30)-N(1)}{30 - 1}$

$Rate = \frac{N(30)-N(1)}{29}$

Calculate N(30) and N(1)

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$N(1) = 100e^{-0.023*1} = 100e^{-0.023} = 97.73$

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aleksandr82 [10.1K]

Answer:

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