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wolverine [178]
3 years ago
14

Please explain to me how to find y. I’m so confused.

Mathematics
1 answer:
koban [17]3 years ago
7 0
Every triangle angles add up to 180.

So because one angle is 90 degrees you would subtract it from 180 to get 90 and then divide it by two which is 45 degrees.

Hope this helps, have a nice day! :)
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Does circumference divided by ratio equal to pi?​
Harlamova29_29 [7]

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How do you find the area of a cube measuring 3ft it has 7sides
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3 years ago
Find the exact value of cos theta​, given that sin thetaequalsStartFraction 15 Over 17 EndFraction and theta is in quadrant II.
vova2212 [387]

Answer:

cos \theta = -\frac{8}{17}

Step-by-step explanation:

For this case we know that:

sin \theta = \frac{15}{17}

And we want to find the value for cos \theta, so then we can use the following basic identity:

cos^2 \theta + sin^2 \theta =1

And if we solve for cos \theta we got:

cos^2 \theta = 1- sin^2 \theta

cos \theta =\pm \sqrt{1-sin^2 \theta}

And if we replace the value given we got:

cos \theta =\pm \sqrt{1- (\frac{15}{17})^2}=\sqrt{\frac{64}{289}}=\frac{\sqrt{64}}{\sqrt{289}}=\frac{8}{17}

For our case we know that the angle is on the II quadrant, and on this quadrant we know that the sine is positive but the cosine is negative so then the correct answer for this case would be:

cos \theta = -\frac{8}{17}

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