Answer:
A) 300
B) 3:1
C) 9 long yellow : 3 long green : 3 short yellow : 1 short green
Explanation:
Long stems (L_) are dominant to short stems (ll)
Yellow seeds (Y_) are dominant to green seeds (yy)
We interbred pea plants with long stems and yellow seeds (L_Y_), but they had a short green parent (llyy) that could have only produced <em>ly</em> gametes, so our plants are heterozygous <em>LlYy</em>.
C) We interbred them LlYy x LlYy. If the two genes are unlinked, this is a typical dihybrid cross and from Mendel's law of independent assortment we know that the offspring will have the following phenotypic ratios:
- 9/16 L_Y_ (Long, yellow)
- 3/16 L_yy (Long, green)
- 3/16 llY_ (short, yellow)
- 1/16 llyy (short, green)
A) 3/16 × 1600 = 300 plants will be long and green.
B)
9/16 + 3/16 = 12/16= 3/4 plants will be yellow;
3/16 + 1/16 = 4/16= 1/4 plants will be green.
The ratio will be 3 yellow : 1 green
Answer:
combustion
Explanation:
glucose is being burnt by air (oxygen) to produce carbon dioxide and water
Given what we know, after you’ve removed a loopful of broth culture from the culture tube you should immediately apply a flame to the open end of the test tube.
<h3>Why would this be the next step?</h3>
Once you have removed the loopful of broth culture from the tube, you should apply a flame to the end of the tube, this is of vital importance. The reason for this is to deny any other contaminants from entering or exiting the culture sample.
Therefore, we can confirm that after you’ve removed a loopful of broth culture from the culture tube you should immediately apply a flame to the open end of the test tube.
To learn more about culture tubes visit:
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