47 -14i
You can work this out in the straight-forward way, or you can recognize that (6-i) is a common factor. In the latter case, you have ...
... = (6-i)(5 + 3-i)
... = (6 -i)(8 -i)
This product of binomials is found in the usual way. Each term of one factor is multiplied by each term of the other factor and the results summed. Of course, i = √-1, so i² = -1.
... = 6·8 -6i -8i +i²
... = 48 -14i -1
... =
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A suitable graphing calculator will work these complex number problems easily.
I believe the correct answer is 2.
<span>
The factors of 98 are 1 ,2,7,14,49,98</span>
the constant term is 12
All the other terms have variables attached to them
Answer:
1. 1/6
2. 1/9
3. 1/10
4.it would still be 9/10
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I cant answer that one sorry
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4 (im a little less confident in this one :( )
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1/4
