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snow_tiger [21]
2 years ago
12

A nonnative fern species is introduced into an area and quickly begins to spread. The number of plants can be modeled by

Mathematics
1 answer:
ivolga24 [154]2 years ago
3 0

Based on the information, there were initially 1200 ferns; the monthly percent rate of change is 68% and this situation is modeled by an exponential growth function

<h3>How to complete the information?</h3>

The given parameters from the question are:

P(n) = 1200(1.68)^n

Where

n represent the number of months

An exponential growth function is represented as:

P(n) = a * (1 + r)^n

Where

a represents the initial value

r represents the rate

By comparison, we have

a = 1200

1 + r = 1.68

This gives

r = 0.68 = 68%

Hence, there were initially 1200 ferns; the monthly percent rate of change is 68% and this situation is modeled by an exponential growth function

Read more about exponential growth function at:

brainly.com/question/2456547

#SPJ1

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Can someone ask me about this, which is algebra, please
krok68 [10]

Answer:

The correct answer is not shown in your picture. You must get a = 60.

Step-by-step explanation:

(1/2)a + (2/3)b = 50

b = 30

(1/2)a + (2/3)(30) = 50

(1/2)a + 20 = 50

(1/2)a + 20 - 20 = 50 - 20

(1/2)a = 30

2 * (1/2)a = 2 * 30

a = 60

The correct answer is not shown in your picture. You must get a = 60.

5 0
3 years ago
A study by the National Athletic Trainers Association surveyed random samples of 1679 high school freshmen and 1366 high school
nekit [7.7K]

Answer:

We conclude that there is no significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids.

Step-by-step explanation:

We are given that a study by the National Athletic Trainers Association surveyed random samples of 1679 high school freshmen and 1366 high school seniors in Illinois.

Results showed that 34 of the freshmen and 24 of the seniors had used anabolic steroids.

Let p_1 = <u><em>proportion of Illinois high school freshmen who have used anabolic steroids.</em></u>

p_2 = <u><em>proportion of Illinois high school seniors who have used anabolic steroids.</em></u>

SO, Null Hypothesis, H_0 : p_1=p_2      {means that there is no significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids}

Alternate Hypothesis, H_A : p_1\neq p_2      {means that there is a significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids}

The test statistics that would be used here <u>Two-sample z test for</u> <u>proportions</u>;

                        T.S. =  \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }  ~ N(0,1)

where, \hat p_1 = sample proportion of high school freshmen who have used anabolic steroids = \frac{34}{1679} = 0.0203

\hat p_2 = sample proportion of high school seniors who have used anabolic steroids = \frac{24}{1366} = 0.0176

n_1 = sample of high school freshmen = 1679

n_2 = sample of high school seniors = 1366

So, <u><em>the test statistics</em></u>  =  \frac{(0.0203-0.0176)-(0)}{\sqrt{\frac{0.0203(1-0.0203)}{1679}+\frac{0.0176(1-0.0176)}{1366} } }

                                     =  0.545

The value of z test statistics is 0.545.

Since, in the question we are not given with the level of significance so we assume it to be 5%. <u>Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.</u>

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that there is no significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids.

3 0
3 years ago
What is the distance between -7.5 and -15.3 on a number line
timama [110]
Okay. To find the distance apart from each other, subtract 15.3 and 7.5. When you do that, you should get 7.8. -7.5 and -15.3 are 7.8 units away on a number line.
8 0
3 years ago
Pleaseeeeee help meeee answer number 3,5 and 7 they are hard for me to do
Liula [17]

Answer:

5. 52+56 < 49x -46x

108< 3x

108/3< 3x/3

36

8 0
2 years ago
Which expression is the same as 6 times 52?
Blizzard [7]

Answer:

B

Step-by-step explanation:

6 times 50 = 300

6 times 2 = 12

300 + 12 = 312

6 times 52 = 312

4 0
3 years ago
Read 2 more answers
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