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2 years ago

A nonnative fern species is introduced into an area and quickly begins to spread. The number of plants can be modeled by

1 answer:

3 0

Based on the information, there were initially 1200 ferns; the monthly percent rate of change is 68% and this situation is modeled by an exponential growth function

<h3>How to complete the information?</h3>

The given parameters from the question are:

P(n) = 1200(1.68)^n

Where

n represent the number of months

An exponential growth function is represented as:

P(n) = a * (1 + r)^n

Where

a represents the initial value

r represents the rate

By comparison, we have

a = 1200

1 + r = 1.68

This gives

r = 0.68 = 68%

Hence, there were initially 1200 ferns; the monthly percent rate of change is 68% and this situation is modeled by an exponential growth function

Read more about exponential growth function at:

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A + 2b = 1<br>2a + b = 8

xxMikexx [17]

Answer:

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4 0

3 years ago

Use the graph below to fill in the blank with the correct number:

Alik [6]

Let
$A(-3,0) \\ B(-2,2) \\ C(0,1) \\ D(1,-2)$

we know that

Point A
$A(-3,0) \\ for x=-3 \\ f(-3)=0$

Point B
$B(-2,2) \\ for x=-2 \\ f(-2)=2$

Point C
$C(0,1) \\ for x=0 \\ f(0)=1$

Point D
$D(1,-2) \\ for x=1 \\ f(1)=-2$

therefore

the answer is
$f(0)=1$

4 0

3 years ago

Read 2 more answers

What is the percent rate of change in function y=(0.96)^x? Determine Whether The Function Represents Exponential Growth Or Expon

mihalych1998 [28]

B
The original value will be multiplied by 0.96 each time, making it 4% less than what it was.

3 0

3 years ago

Read 2 more answers

HI can you help me with this problem?The quantity demanded x for a certain brand of MP3 players is 300 units when the unit price

Vlad [161]

The demand equation is P = -0.05x + 105

STEP - BY - STEP EXPLANATION

What to find?

<em>The demand equation.</em>

The following information is used to solve the problem.

If (x₁ , y₁) and (x₂, y₂) are any dinstinct points on a line a non-vertical line L, then the equation of the line that has a slope(m) and passes through the point (x₁ , y₁) is given by the formula below:

$y-y_1=_{}\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

Assume p, be the unit price and x be the demand when the price is $p.

From the question given, when the unit price x = 300 units, the demand p = $90 and when the unit price x = 1300 units, the demand p = $40

This means the demand curve passes through the points (300, 90) and (1300, 40).

Assume the demand equation is linear, then the line of the equation passes through the points (300, 90) and (1300, 40).

Now;

y=p x₁ =300 y₁ = 90 x₂ = 1300 y₂=40

Substitute the values into the function and simplify.

$p-90=\frac{40-90}{1300-300}(x-300)$

Simplify the above.

$p-90=\frac{-50}{1000}(x-300)$ $p-90=-0.05(x-300)$

Open the parenthesis.

P- 90 = -0.05x + 15

Add 90 to both-side of the equation.

P = -0.05x + 15 + 90

P = -0.05x + 105

Hence, the demand function is P = -0.05x + 105

6 0

1 year ago

used to have a square garage with ft of floor space. recently built an addition to it. The garage is still a square, but now it

Sergio [31]

Answer:

I used to have a square garage with ft of floor space. recently built an addition to it. The garage is still a square, but now it has 50% more floor space. What was the length of one side of the garage originally? What is the length of one side of the garage now? What was the percent increase in the length of one side?

Step-by-step explanation:

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3 years ago