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3 years ago

6 + 5y - 4y + 10 + 3x - X

Mathematics

2 answers:

Kazeer [188]3 years ago

8 0

Answer:

2 + + 1 6

Step-by-step explanation:

Add the numbers:

6 + 5y - 4y + 10 + 3x -x =

1 6 + 5 − 4 + 3 −

Combine like terms:

16 + 5y - 4y +3x - x

16+ 1y + 3x -x

Multiply by 1

16 + 1y + 3x - x

16 + y + 3x - x

Combine like terms:

16 + y + 3x - x

16 + y + 2x

Rearrange terms:

16 + y + 2x

2x + y + 16

Nuetrik [128]3 years ago

7 0

Answer:

16 + y + 2x

Step-by-step explanation:

$6 + 5y - 4y + 10 + 3x - x$

$16 + 5y - 4y + 3x - x$

$5y - 4y = (5 - 4)y = 1y = y$

$16 + y + 3x - x$

$= 16 + y + 2x$

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Answer:

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Step-by-step explanation:

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<h3>Hence the value of c is (-14)/3 .</h3>

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$\displaystyle\\
1 \frac{2}{5} +\Big(-5 \frac{1}{2} \Big) = ? \\ \\ 
1 \frac{2}{5} = \frac{1\times 5+2}{5}=\boxed{\frac{7}{5}} \\ \\ 
-5 \frac{1}{2} =-5 -\frac{1}{2} = \frac{-5\times2-1}{2} =\frac{-10-1}{2}=\frac{-11}{2}= \boxed{-\frac{11}{2} }\\ \\ \texttt{OR} \\ \\ 
-5 \frac{1}{2} = -\Big(5 \frac{1}{2} \Big)= -\Big( \frac{5\times2+1}{2} \Big)=-\Big( \frac{11}{2} \Big)= \boxed{-\frac{11}{2} }$

$\displaystyle\\
\Longrightarrow ~~1 \frac{2}{5} +\Big(-5 \frac{1}{2} \Big) =\frac{7}{5} -\frac{11}{2} = \frac{7\times 2}{5\times 2} -\frac{11\times 5}{2\times 5} = \\ \\ 
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