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ElenaW [278]
2 years ago
9

4 1/2 ​ ÷(−1 3/7​ ) please help and hurry

Mathematics
2 answers:
MAVERICK [17]2 years ago
7 0
4 1/2 = 9/2 -1 3/7 = - 10/7
- 9/2 x 10/7
- 63/20
Answer: - 63/20, -3 3/20, -3.15
myrzilka [38]2 years ago
6 0

Hi! I'm happy to help!

To first solve this, we need to make those mixed numbers improper fractions.

To make 4 1/2 an improper fraction, you have to turn 4 into halves (multiply four by 2) then add the extra half, giving you 9/2.

\frac{9}{2}​ ÷(−1\frac{3}{7}​ )

Now, we turn 1 3/7 into an improper fraction. We turn 1 into sevenths (multiply 1 by 7) then add the other 3 sevenths, giving you 10/7.

\frac{9}{2}​ ÷(−\frac{10}{7}​ )

From here, we need to turn this problem into a multiplication problem in order to solve. Since multiplication is the opposite of division, we need to get the opposite of something, so we use our second fraction and flip it.

\frac{9}{2}​ ×(−\frac{7}{10}​ )

Now, we multiply the top by the top, and the bottom by the bottom. (any positive multiplied by a negative gives a negative)

-\frac{63}{20}

<u>Since we cannot simplify, our final answer is -63/20.</u>

I hope this was helpful, keep learning! :D

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Answer:

A graph shows lap time (seconds) labeled 82 to 98 on the horizontal axis and the number of laps on the vertical axis. 1 lap was 82 to 84 seconds.  4 laps were 84 to 86 seconds. 2 laps were 86 to 88 seconds. 4 laps were 88 to 90 seconds. 6 laps were 90 to 92 seconds. 5 laps were 92 to 94 seconds. 2 laps were 94 to 96 seconds. 0 laps were 96 to 98 seconds

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The given table is presented as follows;

\begin{array}{ccc}Day \ 1 \ lap \ times \ (seconds)&Day \ 2 \ lap \ times \ (seconds)&Day \ 3 \ lap \ times \ (seconds)\\83&87&85\\92&90&86\\91&92&91\\89&91&93\\94&92&91\\93&95&89\\88&90&88\\84&85&84\end{array}The number of laps in the range 82 to 84 seconds = 1

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