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Nesterboy [21]
3 years ago
8

Simplify. (x2 - y2 - 3xy) + (7xy + 3x2)

Mathematics
2 answers:
Dvinal [7]3 years ago
7 0

Answer:

(x² - y² - 3xy) + (7xy + 3x²) = 4x² - y² + 4xy

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Terms/Coefficients

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

(x² - y² - 3xy) + (7xy + 3x²)

<u>Step 2: Simplify</u>

  1. [Order of Operations] Combine like terms (x²):                                              (x² - y² - 3xy) + (7xy + 3x²) = 4x² - y² - 3xy + 7xy
  2. [Order of Operations] Combine like terms (xy):                                             (x² - y² - 3xy) + (7xy + 3x²) = 4x² - y² + 4xy
TEA [102]3 years ago
6 0

Answer:

4x^2-y^2+4xy

Step-by-step explanation:

Just combine like terms and do not forget that your adding the set of parentheses together.

x^2+3x^2

-y^2

-3xy+7xy

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A set of data has a normal distribution with a mean of 50and a standard deviation of 8. What percent of the data should be less
meriva

50% of data will be less than 50

Step-by-step explanation:

A normal distribution has the shape of the graph like a bell.

Given

Mean=50\\SD = 8

we have to find how much data will be less than 50.

So we have to calculate z-score for 50.

z-score=\frac{x-Mean}{SD}\\=\frac{50-50}{8}=0

The z-score is zero. As we have to find the number of values less than 50 we will find the area to the left of curve

P(z

In order to convert the probability into percentage

=0.50*100

=50%

Hence,

50% of data will be less than 50

Keywords: Probability, Area under the curve

Learn more about z-score at:

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3 years ago
Is 816.514 greater than or less than 86.684
lawyer [7]

Answer:

816.514 greater than 86.684

Step-by-step explanation:


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3 years ago
7.2 cw homework help
kati45 [8]

Answer:

31. Yes (Y)

WXYZ ~ DABC

S.F.=4


32. Yes (Y)

GHIJ ~ KLMN

S.F.=2/3


33. Missing length: 16


34. Missing length: 30


35. x=7


36. x=10


Step-by-step explanation:

31. The polygons are similar if:

WX/DA=XY/AB

Then:

WX/DA=24/6→WX/DA=4

XY/AB=16/4→XY/AB=4

Like WX/DA=4=XY/AB, the polygons WXYZ and DABC are similar

Scale Factor: S.F.=XY/DA=XY/AB→S.F.=4


32. The polygons are similar if:

GH/KL=HI/LM=IJ/MN=GJ/KN

Then:

GH/KL=6/9=(6/3)/(9/3)→GH/KL=2/3

HI/LM=4/6=(4/2)/(6/2)→HI/LM=2/3

IJ/MN=4/6=(4/2)/(6/2)→IJ/MN=2/3

GJ/KN=4/6=(4/2)/(6/2)→GJ/KN=2/3

Like GH/KL=HI/LM=IJ/MN=GJ/KN=4, the polygons GHIJ and KLMN are similar

Scale Factor: S.F.=GH/KL=HI/LM=IJ/MN=GJ/KN→S.F.=2/3


33. If the polygons are similar, their sides must be proportional, then:

x/24=10/15

Simplifying the fraction on the right sides of the equation, dividing the numerator ans denominator by 5:

x/24=(10/5)/(15/5)

Dividing:

x/24=2/3

Solving for x: Multiplying both sides of the equation by 24:

24(x/24)=24(2/3)

Multiplying:

x=8(2)

x=16


34. If the polygons are similar, their sides must be proportional, then:

54/63=(54/9)/(63/9)→54/63=6/7

48/56=(48/8)/(56/8)→48/56=6/7

x/35=6/7

Solving for x: Multiplying both sides of the equation by 35:

35(x/35)=35(6/7)

Multiplying:

x=5(6)

x=30


36. (8x-2)/63=42/49

Simplifying the fraction on the right sides of the equation, dividing the numerator ans denominator by 7:

(8x-2)/63=(42/7)/(49/7)

Dividing:

(8x-2)/63=6/7

Solving for x: Multiplying both sides of the equation by 63:

63(8x-2)63=63(6/7)

Multiplying:

8x-2=9(6)

8x-2=54

Adding 2 both sides of the equation:

8x-2+2=54+2

Adding:

8x=56

Dividing both sides of the equation by 8:

8x/8=56/8

Dividing:

x=7


37. (6x-6)/63=42/49=30/35

Simplifying the fractions

(6x-6)/63=(42/7)/(49/7)=(30/5)/(35/5)

Dividing:

(6x-6)/63=6/7

Solving for x: Multiplying both sides of the equation by 63:

63(6x-6)63=63(6/7)

Multiplying:

6x-6=9(6)

6x-6=54

Adding 6 both sides of the equation:

6x-6+6=54+6

Adding:

6x=60

Dividing both sides of the equation by 6:

6x/6=60/6

Dividing:

x=10



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Answer:

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Step-by-step explanation:

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I hope this helps:

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