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3 years ago

What is the equation for the line in slope-intercept form? Enter your answer in the box.

Mathematics

1 answer:

Marina86 [1]3 years ago

3 0

Answer: y=8x

Step-by-step explanation:

Slope-intercept form is y=mx+b, where m is slope and b is y-intercept. To find slope, we take any two points and plug them into $m=\frac{y_2-y_1}{x_2-x_1}$ . Let's use (1,8) and (2,16).

$m=\frac{16-8}{2-1}=\frac{8}{1} =8$

Now, we know that m=8. Looking at the graph, we can see that the y-intercept is b=0 because the line passes through the y-axis at (0,0). To be sure, let's plug in a point into our equation to see if the y-intercept is correct.

y=8x+b [plug in (1,8)]

8=8(1)+b [multiply]

8=8+b [subtract both sides by 8]

b=0

Therefore, our equation is y=8x.

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3. f(x)= |3x -4|<br> D =<br> R=

Natalka [10]

Answer:

Domain = All real numbers

Range = y ≥ 0

Step-by-step explanation:

As for the domain... you can substitute any value for x and get a mathematical response. Therefore... the domain is all real numbers

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3 years ago

Write an equivalent equation that does not contain parentheses for 3(k-x) = -3x-9

amm1812

3(k-x)= -3x-9
3k - 3x = -3x - 9 ← equation without parentheses
3k - 3x + 3x = - 9
3k = -9
k = -9/3
k = -3 ← simplest form

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4 years ago

Find the equation of a line passing through a point (3,5) and perpendicular to the line joining the points (3, 7) and (7, -1)

eduard

Step-by-step explanation:

we start first by finding the gradient of the line

change in y/change in x

7-(-1)/3-7=8/-4

=-2

then for perpendicular lines m1m2=-1

therefore to find the gradient of that line

-2m2=-1

therefore m2=2

so therefore

y-5/x-3=2

so y-5=2x-6

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in the form y= mx +c

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3 years ago

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vlabodo [156]

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3 years ago

HELP PLEASE !!!!!!!!!!!

horrorfan [7]

Answer:

option B

Step-by-step explanation:

$\lim_{x\to \infty} f(x) = \lim_{x \to \infty} (log(x+2)-3 )$

$= \lim_{x \to \infty} ( log(x+2)) - \lim_{x \to \infty} 3\\\\=\infty - 3\\\\= \infty$

$\lim_{x \to 2} f(x) = \lim_{x \to 2} ( log(x+2)) - \lim_{x \to2} 3\\\\$

$= log( 2 + 2 ) - 3\\\\= log 4 - 3\\\\=log(2^2) -3\\\\=2 log 2 -3$

$\lim_{x \to -2} f(x) = \lim_{x \to -2} ( log(x+2)) - \lim_{x \to -2} 3\\\\$ $\lim_{x \to -2}_+ f(x) = \lim_{x \to -2_+} ( log(x+2)) - \lim_{x \to -2_+} 3 = -\infty\\\\\lim_{x \to -2_-} f(x) = \lim_{x \to -2}_- ( log(x+2)) - \lim_{x \to -2}_- 3 = -\infty\\\\\\\lim_{x \to -2} f(x) = - \infty$

6 0

3 years ago

What is the equation for the line in slope-intercept form? Enter your answer in the box.​

What is the equation for the line in slope-intercept form? Enter your answer in the box.