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motikmotik
2 years ago
11

Find the equation of a line passing through a point (3,5) and perpendicular to the line joining the points (3, 7) and (7, -1)

Mathematics
1 answer:
eduard2 years ago
7 0

Step-by-step explanation:

we start first by finding the gradient of the line

change in y/change in x

7-(-1)/3-7=8/-4

=-2

then for perpendicular lines m1m2=-1

therefore to find the gradient of that line

-2m2=-1

therefore m2=2

so therefore

y-5/x-3=2

so y-5=2x-6

y-2x=-1

in the form y= mx +c

then y=2x-1

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Could someone explian to me how to do these two? i’m not sure if i’m doing it right plz help
omeli [17]

Step-by-step explanation:

Before I discuss how to graph both equations, I believe that it is essential to understand the variables and constant related to linear equations.

The <u>slope-intercept form</u> is: y = mx + b, where:

m = slope (which tells you the steepness of the line).

b = y-intercept: this is the point on the graph where it crosses the y-axis. Its coordinates is always formatted as, (0, <em>b</em>). The <u><em>b</em></u> is the y-coordinate of the y-intercept that you use for the equation.

The <u>standard form</u> of linear equations is: Ax + By = C, where:

A, B, C are integers (whole numbers, and cannot be in fraction or decimal forms).  A and B ≠ 0, and <em>A</em> must be a <u>positive integer</u>.

Now that I have defined what the slope-intercept and standard form of linear equations are, we can proceed with working on graphing both equations.

<h3>7. y = -6x - 4</h3>

In this equation, the slope (m) = -6, and the y-intercept (b) = -4.  As an ordered pair, the y-intercept is (0, -4). In order to graph this equation, start by plotting the y-intercept on the graph. Then, use the slope (rise over run) to plot other points on the graph (6 units <em>down</em>, 1 unit <em>run</em>). Your next point should occur at (1, -10).

You could simply connect these two points and draw a line, or plot another point on the graph using the slope technique mentioned in this post.

<h3>8. 3x - 4y = 12</h3>

This equation is in standard form, Ax + By = C.  It is easier to graph a linear equation when it is in its <u>slope-intercept form,</u> y = mx + b.

In order to transform this equation into its slope-intercept form, start by subtracting 3x from both sides of the equation:

3x - 4y = 12

3x - 3x - 4y = - 3x + 12

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Next, divide both sides by -4 to isolate y:

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y = ¾x - 3 ⇒ This is the slope-intercept form where the slope, <em>m</em> = ¾, and the y-intercept is <em>b</em> = -3.

Similar to how we graphed the equation from question 7, start by plotting the y-intercept, (0, -3). Then, use the slope of the equation, <em>m</em> = ¾ (3 units rise, 4 units run) to plot the next point. The next point should occur at (0, 4).

Attached are the graphed equations.  

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