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motikmotik
2 years ago
11

Find the equation of a line passing through a point (3,5) and perpendicular to the line joining the points (3, 7) and (7, -1)

Mathematics
1 answer:
eduard2 years ago
7 0

Step-by-step explanation:

we start first by finding the gradient of the line

change in y/change in x

7-(-1)/3-7=8/-4

=-2

then for perpendicular lines m1m2=-1

therefore to find the gradient of that line

-2m2=-1

therefore m2=2

so therefore

y-5/x-3=2

so y-5=2x-6

y-2x=-1

in the form y= mx +c

then y=2x-1

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Find the area of the trapezoid 14.5 8 19.5​
Svetlanka [38]

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Which one is the height?¿

The formula is

b1+b2 divided by 2 times the height

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3 years ago
From the equation y−3=−2(x+1), identify the slope and a point on the line.
olga2289 [7]

Answer:

slope = - 2, point on line = (- 1, 3 )

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

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4 0
3 years ago
Peter has a coupon for 15% off the price of any item in a sporting good store he wants to buy a pair of sneakers that are priced
aniked [119]

Answer:

$31.44

Step-by-step explanation:

According to the word problem, Peter has a coupon for 15% OFF.

This means the price will reduce by 15%.

To solve this, first, change the percentage (15%) to decimal form.

To do this, divide the percentage by 100.

15 / 100 = 0.15.

0.15 is the decimal form of 15%.

Next, multiply the decimal form of the percentage by the price.

36.99 x 0.15 = 5.5485

Lastly, subtract the product from the original price.

36.99 - 5.5485 = 31.4415

In this case, the product goes above the hundredths place.

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7 0
3 years ago
Which condition is sufficient to show that quadrilateral DEFG is a parallelogram?
Whitepunk [10]

Answer:

Option D

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To use the supplementary property to identify a parallelogram. The condition must be that that the same-side interior angles (consecutive angles) are supplementary.

Thus for parallelogram DEFG

        D --------------------E

         /                      /

     G---------------------F

Thus, we have it that the condition that is most sufficient to show that quadrilateral DEFG is a parallelogram is

∠GDE is supplementary to both ∠DEF and ∠FGD

4 0
3 years ago
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