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Zolol [24]
3 years ago
10

Check all that apply

Mathematics
1 answer:
lozanna [386]3 years ago
3 0

Answer:

D. be congruent

Step-by-step explanation:

vertical angles are angles that are across from each other on intersecting lines and they are always congruent

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Does anyone know this?
Darina [25.2K]

2 x 2 x 2 x 3

Because you are multiplying two, four times

6 0
3 years ago
Convert (-6, -6) from Cartesian coordinates to polar coordinates. Round the length to the nearest 0.01 Express the
Neko [114]

9514 1404 393

Answer:

  (8.49; 225°)

Step-by-step explanation:

The angle is a 3rd-quadrant angle. The reference angle will be ...

  arctan(-6/-6) = 45°

In the 3rd quadrant, the angle is 45° +180° = 225°.

The magnitude of the vector to the point is its distance from the origin:

  √((-6)² +(-6)²) = √(6²·2) = 6√2 ≈ 8.4859 ≈ 8.49

The polar coordinates can be written as (8.49; 225°).

_____

<em>Additional comment</em>

My preferred form for the polar coordinates is 8.49∠225°. Most authors use some sort of notation with parentheses. If parentheses are used, I prefer a semicolon between the coordinate values so they don't get confused with an (x, y) ordered pair that uses a comma. You need to use the coordinate format that is consistent with your curriculum materials.

3 0
2 years ago
PLEASE HELP TRYING TO MAKE HONOR ROLL
FromTheMoon [43]

Answer:

it is B. -11 and 47

Step-by-step explanation:

you have to take away 47 and 11 and it equals 36.

3 0
3 years ago
Urgent pls help!
White raven [17]

Answer:

3^(2/15)

Step-by-step explanation:

Ask in comments if you want.

5 0
3 years ago
#4 home do I find which one it is?
lina2011 [118]
\bf \begin{array}{lllll}&#10;solutions&graphs&slopes\\&#10;----&----&----\\&#10;\textit{exactly one}&&#10;\begin{array}{llll}&#10;\textit{the two lines intersect}\\&#10;\textit{at one point}&#10;\end{array}&\textit{different slopes}\\\\&#10;infinitely\quad many&&#10;\begin{array}{llll}&#10;\textit{the two lines coincide}\\&#10;\textit{one is right on top}\\&#10;\textit{ of the other}&#10;\end{array}&&#10;\begin{array}{llll}&#10;\textit{equal slopes}\\&#10;\textit{equal y-intercepts}&#10;\end{array}&#10;\end{array}

\bf \textit{no solution}\qquad\quad &\textit{lines are parallel} \qquad &&#10;\begin{array}{llll}&#10;\textit{equal slopes}\\&#10;\textit{different y-intercepts}&#10;\end{array}&#10;\end{array}

for example, let's look at the first set

y+3x =5   or  y = -3x+ 5
and               y = -3x + 2
                    y =  m  + b

the slopes are equal, the y-intercepts differ
that means, they're just parallel lines, no solution
8 0
3 years ago
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