You are working with cable that has a loss rate of 5 dB per 100 ft. If you don’t want to lose more than 15 dB, what is the maxim
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Answer:
.
Step-by-step explanation:
The perimeter of a rectangle is the sum of it's side lengths.
A rectangle has 4 sides where it's opposite sides are congruent.
So if one side has measurement w, then there is another side that has measurement w.
If there is one side that has measurement l, then there is another side that has measurement l.
So if you add w+w+l+l you get 2w+2l.
They are giving us that the perimeter is P, so P=2w+2l.
we are being asking to solve for l.
P=2w+2l
First step: Isolate term that contains the l, so get 2l by itself first.
We are going to subtract 2w on both sides giving us:
P-2w=2l
2l=P-2w
Now that we have 2l by itself it is time to perform the last step in getting l by itself.
Second step: Divide both sides by 2.
This gives us:
l=(P-2w)/2
You may separate the fraction like so:
.
I don't know your options but I have solve for l in terms of P and w
and got .
Please let me know if you have further questions with this problem.