All categories

3 years ago

For the standard normal probability distribution, the area to the right of the mean is:

Mathematics

1 answer:

sveticcg [70]3 years ago

7 0

The answer is 0.5. I hope this is helpful.

You might be interested in

What is the range of the equation

a_sh-v [17]

The range of the equation is $y>2$

Explanation:

The given equation is $y=2(4)^{x+3}+2$

We need to determine the range of the equation.

<u>Range:</u>

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

$y=2 \cdot 4^{x+3}+2$

This can be written as $y=2^{1+2(x+3)}+2$

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

$x=2^{1+2(y+3)}+2$

Solving for y, we get;

$x-2=2^{1+2(y+3)}$

Applying the log rule, if f(x) = g(x) then $\ln (f(x))=\ln (g(x))$ , then, we get;

$\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)$

Simplifying, we get;

$(1+2(y+3)) \ln (2)=\ln (x-2)$

Dividing both sides by $\ln (2)$ , we have;

$2 y+7=\frac{\ln (x-2)}{\ln (2)}$

Subtracting 7 from both sides of the equation, we have;

$2 y=\frac{\ln (x-2)}{\ln (2)}-7$

Dividing both sides by 2, we get;

$y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}$

Let us find the positive values for logs.

Thus, we have,;

$x-2>0$

$x>2$

The function domain is $x>2$

By combining the intervals, the range becomes $y>2$

Hence, the range of the equation is $y>2$

7 0

3 years ago

X ⋅ x ⋅ x ⋅ x ⋅ x = ? 5x x(x + 5) x + 5 x5

vampirchik [111]

Answer

x.x.x.x.x = 5x

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

How can you use volume formulas to solve problems?

Katarina [22]

Well, it depends what shape you are using the volume formula for. If it's for a square (I'm assuming) then the volume formula would be:

Side^2

6 0

4 years ago

Find a polynomial function of the lowest degree, with real coefficients, with the given roots.

makvit [3.9K]

Answer:

Step-by-step explanation:

Roots into factors:

x = -4 ----> (x + 4)

x = i -----> (x - i)

x = 5 -----> (x - 5)

(x + i)(x - 4)(x + 5)

(x - i)(x² - 4x + 5x - 20)

(x - i)(x² + x - 20)

x³ + x² - 20x - (ix² + ix - 20i)

x³ + (1 - i)x² - (20 + i)x + 20i

5 0

3 years ago

Which statement is true about the x-intercepts?

N76 [4]

Answer:

The x-intercept is found by setting y = 0, because that will give us the x-value at which the line crosses the x-axis

Step-by-step explanation:

3 0

3 years ago