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3 years ago

Find the common difference of the arithmetic sequence -6, 2, 10

Mathematics

1 answer:

Butoxors [25]3 years ago

7 0

Step-by-step explanation:

-6+8=2 by -6 will cut from 8 and remain 2.

2+8=10 by same way 8 will added to 2 and got 10.

I hope it will help you

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here are five rods a-1 a a a a+3 all measurements are in cm the total length of the five rods is l cm find a formula for l in te

Elenna [48]

Answer:

$I=5a+2$ (simplified form)

Step-by-step explanation:

I is the total length of all the 5 rods.

Each of the 5 parts lengths are $(a-1), a, a, a, (a+3)$ , respectively.

We add all of them and equate it to I:

$I=(a-1)+a+a+a+(a+3)$

Simplifying this, we take like terms and add:

$I=(a-1)+a+a+a+(a+3)\\I=5a-1+3\\I=5a+2$

5 0

3 years ago

In 9 through 28, round each number to the place of the underlined digit

iVinArrow [24]

Since 9 is over 5 it rounds up: 40,000

4 0

2 years ago

Please help please help

Alex Ar [27]

Answer:

1. 3

2. D

3. KE

4. B

5. A

Step-by-step explanation:

those should be your answers

7 0

2 years ago

Read 2 more answers

Find the surface area of the figure below. Leave answers in terms of 7 for answers that contain T. Round to the nearest hundredt

Ksju [112]

Answer:

Hello! 59.2 is our answer

This is because for all the triangles we do 5.4 x 4 = 21.6 then I divide by 2 cause thats the formula when doing triangles so I get 10.8 and sense all the triangle sides our the same I do 10.8 x 4 and get 43.2 then for the bottom side I just have to do 4 x 4 cause thats the formula and get 16 then I add these up so 43.2 + 16 = 59.2 and We get our answer 59.2 Hope this helps!

4 0

2 years ago

Two cars drive from town A to town B at constant speeds. The blue car travels 35 miles per hour and the red car travels 70 miles

ExtremeBDS [4]

We can use the formula d = rt in getting the algebraic equation for the two cars where; d = distance, r = rate, t = time.

Given:
$r_{1}$ (blue car) = 35 miles per hour
$r_{2}$ (red car) = 70 miles per hour
distance between the two towns = 140 miles
$t_{1}$ (blue car)= no. of hours the blue car travels
$t_{2}$ (red car) = no. of hours the red car travels

Linear equation for the blue car
$d=( r_{1})( t_{1})$
$140=(35)( t_{1})$
$140/35= t_{1}$
$t_{1}=4 hours$
blue car travels 4 hours from town A to town B.

Linear equation for the red car
$d=( r_{2})( t_{2})$
$140=(70)( t_{2})$
$140/70= t_{2}$
$t_{2}=2 hours$
red car travels 2 hours from town A to town B.

8 0

3 years ago