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myrzilka [38]
3 years ago
9

Suppose you know that the prices paid for cars are normally distributed with a MEAN or $17,000 and a STANDARD DEVIATION of $500.

Use the EMPIRICAL RULE to find the percentage of buyers who paid
Mathematics
1 answer:
AlekseyPX3 years ago
3 0

Complete question :

Suppose you know that the prices paid for cars are normally distributed with a MEAN or $17,000 and a STANDARD DEVIATION of $500. Use the EMPIRICAL RULE to find the percentage of buyers who paid between 15500 and 17000

Answer:

49.85%

Step-by-step explanation:

Mean = 17000

Standard deviation = 500

Obtain the Z score, which is the number of standard deviations from the mean :

((17000 - 17000) / 500) = 0

((15500 - 17000) / 500) = - 3

-3 to 3 = (3 standard deviations)

However,

The value here is (-3 to 0) ; which is only 3 standard deviations to the left.

3 standard deviation = 99.7% (empirical rule)

Since it is only (-3 to 0) ; which is only 3 standard deviations to the left. ; the percentage will be halved

99.7% / 2 = 49.85%

Hence, percentage of buyers who paid between 15500 and 17000 is 49.85%

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Answer:

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Step-by-step explanation:

Here, we can simply set up an equation using variable <em>x </em>in place of the unknown student/adult tickets.

x = # of <u>adult</u> tickets sold

x + 65 = # of <u>student</u> tickets sold.

1) x + x + 65 = 815 (set both ticket amounts equal to the total)

2) 2x + 65 = 815 (added common variables together)

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4) x = 375 (divided both sides by 2)

5) 815 - 375 = 440 (subtracted the x from the total number of <u>adult</u> tickets, to recieve the amount of <u>childrens</u>' tickets.

Therefore,

Since there were fewer adult tickets sold (-65), 375 is the number of adult tickets, and 440 is the number of student tickets.

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2 years ago
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The quotient of the rational expressions is \rm \dfrac{x^2-x}{x-1}.

<h3>Given that</h3>

Rational Expression; \rm \dfrac{x}{x-1} ÷\rm \dfrac{1}{x+1}

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Which of the following is the quotient of the rational expressions shown here?

<h3>According to the question</h3>

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\rm \dfrac{x}{x-1} ÷\rm \dfrac{1}{x+1}

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