Let the number be n.
Then:
n^2 + (1/n)^2 = 82/9; find n. Find the LCD; it is 9n^2.
Mult all 3 terms by 9n^2:
82*9n^2
9n^4 + 9 = (82/9)(9n^2) => 9n^4 + 9 = ------------
9
Then 9n^4 - 82n^2 + 9 = 0
I used my graphing calculator to find that n = 3.
Let's check: is 3^2 + (1/3)^2 = 82/9?
Is 9 + 1/9 = 82/9?
Is 81 + 1 = 82? YES. So, n=3 is a solution.
Answer:
the blank is p
Step-by-step explanation:
mulitplying but r and dividing by r cancel each other out, so you would be left with p=p
Answer:
1 and 4
Step-by-step explanation:
im not shure dont trust me, im just saying if you are trying to gues, pick those im lucky :)
