<span><span>y = 2 + 2sec(2x)
The upper part of the range will be when the secant has the smallest
positive value up to infinity.
The smallest positive value of the secant is 1
So the minimum of the upper part of the range of
y = 2 + 2sec(2x) is 2 + 2(1) = 2 + 2 = 4
So the upper part of the range is [4, )
The lower part of the range will be from negative infinity
up to when the secant has the largest negative value.
The largest negative value of the secant is -1
So the maximum of the lower part of the range of
y = 2 + 2sec(2x) is 2 + 2(-1) = 2 - 2 = 0
So the lower part of the range is (, 0].
Therefore the range is (, 0] U [4, )
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Answer:
bill is 6 george is 36 and mia is 12
Step-by-step explanation:
6 times 6 is 36 and 1/3 of that is 12. hope I did that right.
Answer:
I think B 82.3%
Step-by-step explanation:
Answer:
The answer is
Step-by-step explanation:
The problem is
First we have to bring x to the other side se we subtract x from both sides
Then we have to put it in order so the answer is
Answer:
23
Step-by-step explanation:
