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3 years ago

The odds against an event are 7 to 1. find the probability that the event will occur.

Mathematics

1 answer:

Lubov Fominskaja [6]3 years ago

7 0

$\dfrac{1}{1+7}=\dfrac{1}{8}=12.5\%$

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Mavis drives 634 miles to visit her grandmother in philadelphia. How many miles does mavis drive if she visits her grandmother 4

Dmitriy789 [7]

Mavis drives = 634 miles.

Mavis visits her grandmother 4 times.

That means, she drives 634 miles each time when she visits her mother.

One time round trip Mavis's house to her gramdmother in philadelphia = 634 miles.

If she visited 4 times, we can multiply one round trip distance by 4 or we can just add that distance four times.

Let us try it by multiplying 4 by 634 .

If we multiply 4 by 634, we get 2536.

Therefore, 2536 miles Mavis drives if she visits her grandmother 4 times.

8 0

3 years ago

140 is what percent of 500?

MAXImum [283]

Answer:

28%

Step-by-step explanation:

5 0

3 years ago

What is the quatient of (×3+6×2+11×+6)÷(×2+4×+3

lapo4ka [179]

Answer:

=21+11x

Step-by-step explanation:

3 0

4 years ago

Image down below thx

damaskus [11]

Answer:

question 2 answer you wrote correct

question 3 answer is 20

3 0

3 years ago

Read 2 more answers

20 people applied for a job. Everyone either has a school certificate or diploma or even both. If 14 have school certificates an

STatiana [176]

Given:

Either has a school certificate or diploma or even both = 20 people

Having school certificates = 14

Having diplomas = 11

To find:

The number of people who have a school certificate only.

Solution:

Let A be the set of people who have school certificates and B be the set of people who have diplomas.

According to the given information, we have

$n(A)=14$

$n(B)=11$

$n(A\cup B)=20$

We know that,

$n(A\cup B)=n(A)+n(B)-n(A\cap B)$

$20=14+11-n(A\cap B)$

$20=25-n(A\cap B)$

Subtract both sides by 25.

$20-25=-n(A\cap B)$

$-5=-n(A\cap B)$

$5=n(A\cap B)$

We need to find the number of people who have a school certificate only, i.e. $n(A\cap B')$ .

$n(A\cap B')=n(A)-n(A\cap B)$

$n(A\cap B')=14-5$

$n(A\cap B')=9$

Therefore, 9 people have a school certificate only.

3 0

3 years ago