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Monica [59]
3 years ago
13

Write 8.12 as a mixed number in simplest form. (It’s a repeating decimals

Mathematics
1 answer:
kicyunya [14]3 years ago
8 0

Answer:

8 3/25 because 8.12 is 8 12/100 and when you simplify 12/100 you get 3/25

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Two grocery stores charge amounts for Henry’s favorite olives mangio’s pounds:3 4 5 6
NISA [10]

Answer:

$6 per pound

Step-by-step explanation:

If you do 3 x 6 you get 1, 4 x 6 is 24, 5 x 6 is 30, 6 x 6 is 36. Those are the numbers that they cost. If this helped please consider giving it brainliest.

- •Trix•

( Yes I know my -•Trix• is not my user but its what I would change it to if I could but I can't)

8 0
2 years ago
4x−2y=14 y=12x−1 solve by substitution
Tatiana [17]

Answer:

x= -3/5

Step-by-step explanation:

4x-2y=14

y=12x-1

4x-2(12x-1)=14

4x-24x+2=14

4x-24x=12

-20x=12

×= -12/20

x= -3/5

8 0
3 years ago
Please help me for the love of God if i fail I have to repeat the class
Elena-2011 [213]

\theta is in quadrant I, so \cos\theta>0.

x is in quadrant II, so \sin x>0.

Recall that for any angle \alpha,

\sin^2\alpha+\cos^2\alpha=1

Then with the conditions determined above, we get

\cos\theta=\sqrt{1-\left(\dfrac45\right)^2}=\dfrac35

and

\sin x=\sqrt{1-\left(-\dfrac5{13}\right)^2}=\dfrac{12}{13}

Now recall the compound angle formulas:

\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta

\cos(\alpha\pm\beta)=\cos\alpha\cos\beta\mp\sin\alpha\sin\beta

\sin2\alpha=2\sin\alpha\cos\alpha

\cos2\alpha=\cos^2\alpha-\sin^2\alpha

as well as the definition of tangent:

\tan\alpha=\dfrac{\sin\alpha}{\cos\alpha}

Then

1. \sin(\theta+x)=\sin\theta\cos x+\cos\theta\sin x=\dfrac{16}{65}

2. \cos(\theta-x)=\cos\theta\cos x+\sin\theta\sin x=\dfrac{33}{65}

3. \tan(\theta+x)=\dfrac{\sin(\theta+x)}{\cos(\theta+x)}=-\dfrac{16}{63}

4. \sin2\theta=2\sin\theta\cos\theta=\dfrac{24}{25}

5. \cos2x=\cos^2x-\sin^2x=-\dfrac{119}{169}

6. \tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=-\dfrac{24}7

7. A bit more work required here. Recall the half-angle identities:

\cos^2\dfrac\alpha2=\dfrac{1+\cos\alpha}2

\sin^2\dfrac\alpha2=\dfrac{1-\cos\alpha}2

\implies\tan^2\dfrac\alpha2=\dfrac{1-\cos\alpha}{1+\cos\alpha}

Because x is in quadrant II, we know that \dfrac x2 is in quadrant I. Specifically, we know \dfrac\pi2, so \dfrac\pi4. In this quadrant, we have \tan\dfrac x2>0, so

\tan\dfrac x2=\sqrt{\dfrac{1-\cos x}{1+\cos x}}=\dfrac32

8. \sin3\theta=\sin(\theta+2\theta)=\dfrac{44}{125}

6 0
3 years ago
Can someone take 3 min for there time and help me with this please??
seropon [69]
Since the left side of the equation says f(5), then plug in 5 for x. 

So, it is: 
              
-4|5| + 3
= -20 + 3
= 23 
4 0
3 years ago
Help please.! and thank you
Alexxx [7]

Answer:

common difference is 4

Step-by-step explanation:

12-4=8

8-4=4

8 0
2 years ago
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