All categories

2 years ago

Factor the expression by taking out the greatest common factor. 9x^2y - 6xy^2

Mathematics

1 answer:

Tcecarenko [31]2 years ago

3 0

The greatest common factor of the two terms is 3 x y .

When factored, the expression is

3 x y (3x - 2y)

You might be interested in

Mathematics need help hurry and wander this question ** picture involved**

ser-zykov [4K]

Answer:

radius = 15ft

diameter = 30ft

Step-by-step explanation:

7 0

2 years ago

Determine the area of the triangular ABC with AC =5cm and height DB=30mm

seropon [69]

Answer:

Step-by-step explanation:

AC² = AD² + DB ²

25 = AD² + 9

AD²= 25 - 9

AD² = 16

AD = 4

Area = 4*3 /2

= 6cm

4 0

3 years ago

M is inversely proportional to r if m= 9 when r= 4 find m when r=2

bazaltina [42]

m=18 when r = 2.

Step-by-step explanation:

Given,

m∝ $\frac{1}{r}$

So,

m = k× $\frac{1}{r}$ ,--------eq 1, here k is the constant.

To find the value of m when r = 2

At first we need to find the value of k

Solution

Now,

Putting the values of m=9 and r = 4 in eq 1 we get,

9 = $\frac{k}{4}$

or, k = 36

So, eq 1 can be written as m= $\frac{36}{r}$

Now, we put r =2

m = $\frac{36}{2}$

or, m= 18

Hence,

m=18 when r = 2.

4 0

2 years ago

For every 15 students there are 3 teachers in the school. Based on this information, about how many teachers are in a school wit

Yuliya22 [10]

This means for every 5 students there will be 1 teacher so 550/5=110
So answer is 110 teachers

3 0

2 years ago

Read 2 more answers

From a practice assignment:<br>solve the following differential equation given initial conditions

hodyreva [135]

If $y' = e^y \sin(x)$ and $y(-\pi)=0$ , separate variables in the differential equation to get

$e^{-y} \, dy = \sin(x) \, dx$

Integrate both sides:

$\displaystyle \int e^{-y} \, dy = \int \sin(x) \, dx \implies -e^{-y} = -\cos(x) + C$

Use the initial condition to solve for $C$ :

$-e^{-0} = -\cos(-\pi) + C \implies -1 = 1 + C \implies C = -2$

Then the particular solution to the initial value problem is

$-e^{-y} = -\cos(x) - 2 \implies e^{-y} = \cos(x) + 2$

(A)

4 0

1 year ago