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zlopas [31]
3 years ago
9

Find the volume of a CONE, that has a radius of 2 inches and a height of 8 inches long​

Mathematics
2 answers:
alisha [4.7K]3 years ago
8 0

Answer:

Volume =

\pi  \: r2 \: h \div 3 = \pi2 { \: }^{2} 8 \div 3

= 33.51032

answer

kolezko [41]3 years ago
4 0

Answer:

Step-by-step explanation:

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When 0.5(20x – 50y + 36) – 0.25(–100x + 40y – 12) is simplified, what is the resulting expression?
xz_007 [3.2K]
Distribute -

(Multiplying by 0.5 is same as divide by 2)
10x-25x+18 - 25x -10y + 3
The answer is C
5 0
3 years ago
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HALP NEEDED
wel
Answer: the y intercept is -5

You can use the slope intercept form to find the answer. Aka y = mx + b

In this equation m is equal to the slope and b is equal to the y-intercept.

We already know the slope, 4. And we have two different point we can choose from. I’ll show how to solve with the first (1,-1) point.

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3 years ago
The probability that a lab specimen contains high levels of contamination is 0.14. A group of 4 independent samples are checked.
Shtirlitz [24]

Answer:

a) 0.5470 = 54.70% probability that none contain high levels of contamination.

b) 0.3562 = 35.62% probability that exactly one contains high levels of contamination.

c) 0.4530 = 45.30% probability that at least one contains high levels of contamination.

Step-by-step explanation:

For each sample, there are only two possible outcomes. Either they contain high levels of contamination, or they do not. The samples are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that a lab specimen contains high levels of contamination is 0.14.

This means that p = 0.14

A group of 4 independent samples are checked.

This means that n = 4

(a) What is the probability that none contain high levels of contamination?

This is P(X = 0)

P(X = 0) = C_{4,0}.(0.14)^{0}.(0.86)^{4} = 0.5470

0.5470 = 54.70% probability that none contain high levels of contamination.

(b) What is the probability that exactly one contains high levels of contamination?

This is P(X = 1)

P(X = 1) = C_{4,1}.(0.14)^{1}.(0.86)^{3} = 0.3562

0.3562 = 35.62% probability that exactly one contains high levels of contamination.

(c) What is the probability that at least one contains high levels of contamination?

Either none of the samples contain high levels of contamination, or at least one does. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want to find P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.5470 = 0.4530

0.4530 = 45.30% probability that at least one contains high levels of contamination.

8 0
3 years ago
Which expression is equivalent to 16 × 3?
never [62]

Answer: A

Step-by-step explanation:

X times Y = Y times X

The order doesn't matter.

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Can you help me?
Semenov [28]

Answer:

0=0

Step-by-step explanation:

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