It is neither.
To be even, f(x) must equal f(-x).
If you substitute -x for x, you'd get
y = (-x)^2 - 2(-x) -8
y = x^2 +2x -8
This is not the same as the original, so this is not even.
To be odd, f(x) must equal -f(-x).
If you take the -x substitution from the last step and then multiply it by -1, you'd have:
y = -1 (x^2 +2x -8)
y = -x^2 -2x +8
This is not the same as the original either.
The function is neither even nor odd.
Answer:
you too
Step-by-step explanation:
Hello from MrBillDoesMath!
Answer:
Take you pick below! (either x 8 or x = 7.01, approx, depending how the question is interpreted)
Discussion:
Interpretation 1
If the question is
2^(x -1) = 128, then as 2^7 = 128,
x-1 = 7 so x = 8
Interpretation 2
If the question is (2^x -1) = 128, then..
2^x = 128 + 1 = 129 =>
log(2^x) = log(129) =>
xlog(2) = log(129) =>
x = log (129) / log2 = 7.01
Regards,
MrB
