Answer:
y = -4
Step-by-step explanation:
Solve the following system:
{4 x + 5 y = -12 | (equation 1)
3 y - 2 x = -16 | (equation 2)
Add 1/2 × (equation 1) to equation 2:
{4 x + 5 y = -12 | (equation 1)
0 x+(11 y)/2 = -22 | (equation 2)
Multiply equation 2 by 2/11:
{4 x + 5 y = -12 | (equation 1)
0 x+y = -4 | (equation 2)
Subtract 5 × (equation 2) from equation 1:
{4 x+0 y = 8 | (equation 1)
0 x+y = -4 | (equation 2)
Divide equation 1 by 4:
{x+0 y = 2 | (equation 1)
0 x+y = -4 | (equation 2)
Collect results:
Answer: {x = 2
, y = -4
Answer:
Step-by-step explanation:
a. Money held by individuals in savings accounts is part of the M2 money supply, but not part ofthe M1 money supply. Therefore, when Jane withdraws $500 cash from her savings account,the M1 money supply increases by $500. However, the M2 money supply does not changebecause the M1 money supply is included as part of the M2 money supply.b. Money held by banks and governments is not included as part of the money supply. Therefore,when Jane uses $300 to pay her income tax to the U.S. Treasury, that total of $300 is taken out ofboth the M1 and M2 money supplies. When Jane deposits the remaining cash ($80) into hersavings account, the M1 money supply is reduced by that amount, but it does not affect the M2money supply. Therefore, Jane's actions cause the M2 money supply to change by $300 (theamount used to pay her taxes) and the M1 money supply to change by $380 (the amount used topay her taxes plus the amount that was deposited into her savings account). Note that it does notmatter that Jane no longer has the $120 she used to pay for the gold clubs, as the funds remainsin someone else's checking account. So this amount is neither removed from the M1 moneysupply nor the M2 money supply.NumericResponseDifficulty: 03 HardLearning Objective: 1402 List anddescribe the components of the U.S.money supply.5000380300References
The length of JK rounded to the nearest hundredth is 4.72
y = sqrt(x) .... parent function
y = sqrt(x+2) .... replace x with x+2 to shift 2 units to the left
y = sqrt(x+2)+3 ... add on 3 to move 3 units up
y = sqrt(-x+2)+3 ... replace x with -x to reflect over y axis
<h3>Answer: y = sqrt(-x+2)+3</h3>
Let's solve your equation step-by-step.
2(3x−1)=−6x−2
Step 1: Simplify both sides of the equation.
2(3x−1)=−6x−2
(2)(3x)+(2)(−1)=−6x+−2(Distribute)
6x+−2=−6x+−2
6x−2=−6x−2
Step 2: Add 6x to both sides.
6x−2+6x=−6x−2+6x
12x−2=−2
Step 3: Add 2 to both sides.
12x−2+2=−2+2
12x=0
Step 4: Divide both sides by 12.
12x/12= 0/12
x=0
Answer:
x=0
HOPE THIS HELPS!!! :)
