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sweet-ann [11.9K]
4 years ago
10

What are two factors of -72 that add up to 6

Mathematics
1 answer:
makvit [3.9K]4 years ago
7 0
-6 and 12.
(-6 x 12) = -72 and (-6 + 12) = 6
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Is 3pi/4pi a rational number?
Natali5045456 [20]

Answer:No

Step-by-step explanation:

Pi is irrational

4 0
3 years ago
If XX is a binomial random variable, compute the mean, the standard deviation, and the variance for each of the following cases:
Liula [17]

Answer:

(a) The mean, variance and standard deviation of <em>X </em>are 1.60, 0.96 and 0.98 respectively.

(b) The mean, variance and standard deviation of <em>X </em>are 3.20, 0.64 and 0.80 respectively.

(c) The mean, variance and standard deviation of <em>X </em>are 1.50, 0.75 and 0.87 respectively.

(d) The mean, variance and standard deviation of <em>X </em>are 4.00, 0.80 and 0.89 respectively.

Step-by-step explanation:

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The mean, variance and standard deviation of <em>X</em> are:

\mu=np\\\sigma^{2}=np(1-p)\\\sigma=\sqrt{np(1-p)}

(a)

For <em>n</em> = 4 and <em>p</em> = 0.40 compute the mean, variance and standard deviation of <em>X </em>as follows:

\mu=np=4\times0.40=1.60\\\sigma^{2}=np(1-p)=4\times0.40\times(1-0.40)=0.96\\\sigma=\sqrt{np(1-p)}=\sqrt{0.96}=0.98

Thus, the mean, variance and standard deviation of <em>X </em>are 1.60, 0.96 and 0.98 respectively.

(b)

For <em>n</em> = 4 and <em>p</em> = 0.80 compute the mean, variance and standard deviation of <em>X </em>as follows:

\mu=np=4\times0.80=3.20\\\sigma^{2}=np(1-p)=4\times0.80\times(1-0.80)=0.64\\\sigma=\sqrt{np(1-p)}=\sqrt{0.64}=0.80

Thus, the mean, variance and standard deviation of <em>X </em>are 3.20, 0.64 and 0.80 respectively.

(c)

For <em>n</em> = 3 and <em>p</em> = 0.50 compute the mean, variance and standard deviation of <em>X </em>as follows:

\mu=np=3\times0.50=1.50\\\sigma^{2}=np(1-p)=3\times0.50\times(1-0.50)=0.75\\\sigma=\sqrt{np(1-p)}=\sqrt{0.75}=0.87

Thus, the mean, variance and standard deviation of <em>X </em>are 1.50, 0.75 and 0.87 respectively.

(d)

For <em>n</em> = 5 and <em>p</em> = 0.80 compute the mean, variance and standard deviation of <em>X </em>as follows:

\mu=np=5\times0.80=4.00\\\sigma^{2}=np(1-p)=5\times0.80\times(1-0.80)=0.80\\\sigma=\sqrt{np(1-p)}=\sqrt{0.80}=0.89

Thus, the mean, variance and standard deviation of <em>X </em>are 4.00, 0.80 and 0.89 respectively.

6 0
3 years ago
how many quarts of pure antifreeze must be added to 6 quarts of a 10% antifreeze solution to obtain a 40% antifreeze solution
saveliy_v [14]
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the mixture will be say, "y" amount of 40% antifreeze, thus, the concentrated amount in it will be (40/100) * y or 0.4y.

thus

\bf \begin{array}{lccclll}&#10;&amount(quarts)&concentration&&#10;\begin{array}{llll}&#10;concentrated\\&#10;amount&#10;\end{array}\\&#10;&------&------&------\\&#10;\textit{pure antifreeze}&x&1.00&1x\\&#10;\textit{10\% solution}&6&0.10&0.6\\&#10;------&------&------&------\\&#10;mixture&y&0.40&0.4y&#10;\end{array}

now, bear in mind that, whatever "x" is,
x + 6 = y    <--- the amounts added must yield the amount of the mixture

and x + 0.6 = 0.4y <--- the contrated amounts sum will also add up to the mixture's

\bf \begin{cases}&#10;x+6=\boxed{y}\\&#10;x+0.6=0.4y\\&#10;----------\\&#10;x+0.6=0.4\left( \boxed{x+6} \right)&#10;\end{cases}&#10;\\\\\\&#10;x+0.6=0.4x+2.4\implies 0.6x=1.8\implies x=\cfrac{1.8}{0.6}

4 0
3 years ago
Read 2 more answers
State the degree and leading coefficient of each polynomial in one variable -12-8x^2+5x-21x^7
leonid [27]

Answer:

The degree is 7 and the leading coefficient is -21.

Step-by-step explanation:

The degree of an equation is found using the highest exponent on the variable in the equation.

-12-8x^2+5x-21x^7 has the term x^7 so its degree is 7

The leading coefficient is the coefficient of the term with the highest degree. The coefficient of x^7 is -21.

4 0
3 years ago
standing on the street, the top of a building has an angle of elevation of 20 degrees. You walk 300 feet directly toward the bui
densk [106]

Answer:

The value of height of the building  h = 509.2 feet

Step-by-step explanation:

From the Δ A B C

\tan 25 = \frac{h}{y}

⇒ h = y \tan 25°  ------- (1)

From Δ A B D

\tan 20 = \frac{h}{y + 300}

⇒ h = ( y + 300 ) \tan20° ------- (2)

Equation 1 = Equation 2

⇒ y \tan 25° = ( y + 300 ) \tan20°

⇒ 0.46 y = 0.36 y + 109.2

⇒ 0.1 y = 109.2

⇒ y = 1092 feet

Put this value of y in equation ( 1 ) we get,

⇒ h = 1092 × tan 25°

⇒ h = 509.2 feet

This is the value of height of the building.

8 0
3 years ago
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