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3 years ago

Write the expression as a sum and/or a difference of logarithms, with all variables to the first degree.

Mathematics

1 answer:

andreyandreev [35.5K]3 years ago

7 0

Answer:

ln 2 + 2 ln x + 8 ln y

Step-by-step explanation:

Use of properties

log ab = log a + log b
log a^b = b log a

Given expression

In 2x^2y^8

Simplifying

In 2x^2y^8 =
ln 2 + ln x^2 + ln y^8 =
ln 2 + 2 ln x + 8 ln y

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At dinner, the meal cost $22 and a $1.87 sales tax was added to the bill. What would be the total amount if the meal cost $80.

Helen [10]

1.87 is 8.5% of 22 so 8.5% of 80 is 0.085 x 80 so $6.80

3 0

2 years ago

Need help with working perimeter and area please

SVETLANKA909090 [29]

Answer:

Area = 228 m²

Perimeter = 60 m

Step-by-step explanation:

The figure given shows a rectangle that has a cut triangular portion.

✔️Area of the figure = area of rectangle - area of the triangular cut portion

= L*W + ½*bh

Where,

L = 20 m

W = 12 m

b = 20 - (8 + 8) = 4 m

h = 6 m

Plug in the values

Area = 20*12 - ½*4*6

Area = 240 - 12

Area = 228 m²

✔️Perimeter = perimeter of rectangle - base of the triangular cut portion

= 2(L + W) - b

L = 20 m

W = 12 m

b = b = 20 - (8 + 8) = 4 m

Plug in the values

Perimeter = 2(20 + 12) - 4

= 2(32) - 4

= 64 - 4

Perimeter = 60 m

5 0

3 years ago

Solve the system of equations using multiplication. 3x – 3y = –3 5x – y = –13 What is the solution of the system?

love history [14]

ANSWER

The solution is

x=-3,y=-2

EXPLANATION

First equation

3x – 3y = –3

Second Equation:

5x – y = –13

Multiply the second equation by 3 to get:

Third equation:

15x-3y=-39

Subtract the first equation from the third equation:

$15x - 3x = - 39 - - 3$

$12x = - 36$

Divide both sides by 12,

$x = \frac{ - 36}{12} = - 3$

Put x=-3 into the first equation:

$3( - 3) - 3y = - 3$

$- 9 - 3y = - 3$

Group like terms,

$- 3y = - 3 + 9$

$- 3y = 6$

$y = - 2$

The solution is

x=-3,y=-2

6 0

3 years ago

Which of the following could be used to calculate the area of a sector in the circle shown below

lara [203]

Answer:

Therefore the Last option is correct

$\textrm{Area of Sector ACD}=\pi (8\ in)^{2}\times (\frac{42}{360})$

Step-by-step explanation:

Given:

Radius = r = 8 in

θ = 42°

To Find:

Area of Sector = ?

Solution:

We know that

$\textrm{Area of Sector}=\pi (Radius)^{2}\times \frac{\theta}{360}$

Substituting the given values in the formula we get

$\textrm{Area of Sector ACD}=\pi (8\ in)^{2}\times (\frac{42}{360})$

Which is the required Answer.

Therefore the Last option is correct

$\textrm{Area of Sector ACD}=\pi (8\ in)^{2}\times (\frac{42}{360})$

8 0

2 years ago

URGENT NEED HELP FAST LINKS WILL BE REPORTED

dolphi86 [110]

Answer:

model B is shaded to represent 37.5%

here,

=3÷8×100%

=37.5%

7 0

3 years ago