Please help me solve this equation

Mathematics

1 answer:

Zielflug [23.3K]2 years ago

3 0

I hope it will help you . But I have confused whether you have asked the second question or not . If you have asked , please send that question .

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Which pair of ratios form a proportion?

boyakko [2]

5:8 and 20:32 would be a proportion.

Easy way to find this:
Set up the proportion as a fraction.
Use the cross product property. Multiply the diagonals and if the products of the diagonals are the same, then they are proportional.

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3 years ago

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What is the equation of the following line written in general form (4,5) (1,2)

a_sh-v [17]

The answer is y= 1 + 1x

because the slope is 1 shown by this table:
1,2
2,3
3,4
4,5

and if the slope is one then 2-1 is 1 and the y intercept is 0,1.

4 0

3 years ago

Will give brainliest to correct answer.

kirill [66]

It's going to be kind of crazy, but you need to use Pythagorean's Theorem for this. That will look like this: $(2 \sqrt{x} +1)^2=( \sqrt{x} +1)^2+(2 \sqrt{x} )^2$ . FOIL out the left side to get $4x+4 \sqrt{x} +1$ . FOIL out the first of the 2 expressions on the right to get $x+2 \sqrt{x} +1$ , and the second of the 2 to get 4x. Our equation now looks like this: $4x+4 \sqrt{x} +1=x+2 \sqrt{x} +1+4x$ . Combine like terms to get an equation that still has square roots in it that we have to deal with: $4x-x-4x=-2 \sqrt{x}$ and $x=2 \sqrt{x}$ . We will square both sides to get rid of the square root sign. $x^{2} =2x$ . This is a polynomial now that can be factored to solve for x. Bring the 2x over by subtraction and set the polynomial equal to 0. $x^{2} -2x=0$ . Factor out an x, leaving us with x(x-2)=0. That means that x = 0 or x - 2 = 0 and x = 2. Of course if we are solving for the length of a side we know it can't have a side length of 0, so it must have a side length that is a multiple of 2. x = 2

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3 years ago

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Melissa used 4 cups of sugar to bake 54 cookies. If she’s only used 1 cup of sugar, what would be an equivalent ratio of cups to

daser333 [38]

Answer:

$\frac{2}{27}$