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Katena32 [7]
3 years ago
15

What is the area of the triangle? On a coordinate plane, a triangle has a base of 8 units and a height of 6 units. 24 square uni

ts 32 square units 48 square units 96 square units
Mathematics
2 answers:
Dafna1 [17]3 years ago
7 0

Answer:

24 square units

Step-by-step explanation:

area of a triangle formula: 1/2bh

where b=base

and h=height

so b=8

and h=6

hence 1/2*8*6=24

hence, 24squnits is the answer

Hope this helps!

LekaFEV [45]3 years ago
6 0

Answer:

24

Step-by-step explanation:

8*6=48/2=24

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100% all of them

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Determine if the conclusion of salad. Give a thorough explanation of your answer. Given segment AC is perpendicular to segment c
serious [3.7K]

The given conclusion that ABCD is a square is not valid.

Given that, AC⊥BD and AC≅BD.

We need to determine if the given conclusion is valid.

<h3>What are the properties of squares?</h3>

A square is a closed figure with four equal sides and the interior angles of a square are equal to 90°. A square can have a wide range of properties. Some of the important properties of a square are given below.

  • A square is a quadrilateral with 4 sides and 4 vertices.
  • All four sides of the square are equal to each other.
  • The opposite sides of a square are parallel to each other.
  • The interior angle of a square at each vertex is 90°.
  • The diagonals of a square bisect each other at 90°.
  • The length of the diagonals is equal.

Given that, the diagonals of a quadrilateral are perpendicular to each other and the diagonals of a quadrilateral are equal.

Now, from the properties of a square, we understood that the diagonals of a square are perpendicular to each other and the diagonals of a square are equal.

So, the given quadrilateral can be a square. But only with these two properties can not conclude the quadrilateral is a square.

Therefore, the given conclusion that ABCD is a square is not valid.

To learn more about the properties of a square visit:

brainly.com/question/20377250.

#SPJ1

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2 years ago
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1/2[sin a cos b +cos a sin b + sin A cos B - cos A sin B]

1/2[2sin a cos b]

sin a cos b

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