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2 years ago

Solve by substitution. X = y + 3 3x + y = 25

1 answer:

3 0

1.distribute
3y+9+y=25
2. combine like terms
4y+9=25
3. subtract 9 from both sides
4y=16
4. divide
Solution: y=4
and for X it would be
X= (4) +3
X=7
so the Final solution is (7,4)

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If y varies directly with x, and y = 2 when x = −4, what is the value of y when x = 20

Klio2033 [76]

Answer:

y = - 10

Step-by-step explanation:

Given that y varies directly with x then the equation relating them is

y = kx ← k is the constant of variation

To find k use the condition y = 2 when x = - 4, that is

2 = - 4k ( divide both sides by - 4 )

= k, that is

k = -

y = - x ← equation of variation

When x = 20, then

y = - × 20 = - 10

3 0

3 years ago

Solve |x – 4| + 6 = 17.

const2013 [10]

Answer:

$\mathrm{C)\:}x=15,\:-7$

Step-by-step explanation:

For $|a-b|=c$ , there are two possible cases:

$\begin{cases}a-b=c\\a-b=-c\\\end{cases}$

Solving for both cases, we get:

$\begin{cases}x-4+6=17, \:x+2=17, \: \fbox{$x=15$}\\-(x-4)+6=17,\: -x+10=17, \: -x=7, \:, \fbox{$x=-7$}\\\end{cases}$

6 0

2 years ago

Pls help me with my homework

katovenus [111]

9^-2 = 1/81 or 0.0123
When there is a negative in front of the exponent it makes a fraction. It is usually just 1/the number it equals if it were positive.

4 0

2 years ago

Read 2 more answers

The ordered pair (4, -8) is in the 4th quadrant if we took the opposite of the x- value and the opposite of the y-value, which q

harina [27]

9514 1404 393

Answer:

2nd quadrant

Step-by-step explanation:

Reversing the signs of both coordinates reflects the point across the origin. The quadrant diagonally opposite quadrant 4 is quadrant 2.

_____

You recall that quadrants are numbered 1 to 4 counterclockwise, starting from upper right.

8 0

3 years ago

How many terms are in a^2-ab+8b+b^2-1

DanielleElmas [232]

Remember that the terms of a polynomial are the parts of the polynomial separating by addition and subtraction; in other words, the parts separated by (+) and (-) signs. Knowing this, we can separate the terms of our polynomial:
$a^2-ab+8b+b^2-1$
- First term: $a^2$
- Second term: $-ab$
- Third term: $8b$
- Fourth term: $b^2$
- Fifth term: $-1$

We can conclude that there are 5 terms in the polynomial $a^2-ab+8b+b^2-1$ .

8 0

2 years ago