Answer: 1976
Steps:
Let t* be the year in which the population reached a count of 8920. Solve for t*:

The population grew to the number 8920 in 36 years past 1940, i.e., 1976
i hope my handwriting isnt too bad and that this helps!
Answer:
slope = 
Step-by-step explanation:
Calculate the slope m using the slope formula
m = ( y₂ - y₁ ) / ( x₂ - x₁ )
with (x₁, y₁ ) = (- 6, - 5) and (x₂, y₂ ) = (4, 4)
m=
= 
Answer:
b) 5314
c) ln 2.7
d) 4.6 hrs
<u>Step-by-step explanation:</u>


Answer:

Step-by-step explanation:
To find the distance between any two points, we can use the distance formula:

Our first point, A, is at (1, 1) and our second point, B, is at (-2, 8).
Let's let A(1, 1) be (x₁, y₁) and B(-2, 8) be (x₂, y₂). Substitute this into the distance formula:

Subtract:

Square:

Add:

This cannot be simplified.
So, the distance between the two points is √58 or about 7.6 units.
And we're done!
So... where's my cookie :)?