Strictly speaking, x^2 + 2x + 4 doesn't have solutions; if you want solutions, you must equate <span>x^2 + 2x + 4 to zero:
</span>x^2 + 2x + 4= 0. "Completing the square" seems to be the easiest way to go here:
rewrite x^2 + 2x + 4 as x^2 + 2x + 1^2 - 1^2 = -4, or
(x+1)^2 = -3
or x+1 =i*(plus or minus sqrt(3))
or x = -1 plus or minus i*sqrt(3)
This problem, like any other quadratic equation, has two roots. Note that the fourth possible answer constitutes one part of the two part solution found above.
To get y you can move the x's to one side, so 120y=500-35x
then you can isolate the y, y= 500/120-35x/120
:)
What is the question that u need help with
Okay so for 2x-y > 3
Subtract -2 from each side
-y>-2x+3
Divide by -1
And when you divid you gotta switch signs
So it’s y<2x-3
3x-5y less than and equal to 25
Subtract 3
-5y is less than and equal to -3x+25
Then divide by -5
Flip since we divide
Y more than and equal to 3/5x-5
We always flip signs when we divid or multiple
I hope this help
Sorry if I’m wrong
