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2 years ago

7

Can you please help me solve this equation?

1 answer:

TiliK225 [7]2 years ago

4 0

Answer: ((T/(2pi))^2)g

Step-by-step explanation: just solve for L

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c

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2 years ago

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3 years ago

2x + 2y = -4<br> 3x - 2y = 9

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2 years ago

A rectangular garden has links twice as great as it's with a second rectangular garden has the same link as the first garden and

irinina [24]

Solution :

For the bigger rectangle

Width of bigger rectangle = W

Length of bigger rectangle, L = 2W

For the smaller rectangle

Width , w = W+4

Length, l = L = 2W

Area, a =120 $m^2$

Now we know,

Area = length x width

$a=l \times w$

$120=(2W) \times (W+4)$

$120=2W^2 + 8W$

$2W^2+8W-120=0$

$W^2+4W-60=0$

$(W+10)(W-6) = 0$

We get, either $W=-10$ (rejecting)

or $W=6$

∴ length of the bigger rectangle, $L=2W$

= 2(6)

= 12 m

Length of the smaller rectangle, $L=2W$

= 2(6)

= 12 m

Hence, the length of the two gardens is 12 m.

6 0

2 years ago