Question

Find the value of x in the isosceles triangle shown below.​

Answer 1

Answer:

Option A : $x=\sqrt{60}$

Step-by-step explanation:

We will use the Pythagoras theorem here.

We have the hypotenuse as 8 units

We have the base as x and perpendicular side as 2 units.

Applying Pythagoras theorem,

$x^{2} +2^{2} =8^{2}$

=> $x^{2} +4=64$

=> $x^{2} =64-4$

=> $x^{2} =60$

=> $x=\sqrt{60}$

Hence, option A is the answer.

Answer 2

Answer: A, x = square root of 60.

Step-by-step explanation:

Use the Pythagorean Theorem, a^2 + b^2 = c^2.

8^2 = 2^2 + x^2

x^2 = 8^2 - 2^2

x^2 = 64 - 4

x^2 = 60

x = sqrt of 60