Answer:
(a) 
(b)
Step-by-step explanation:
Let´s use Divided Differences Method of Polynomial Interpolation given by this iteration:
![f[x_k,x_k_+_1,...,x_k_+_i]=\frac{f[x_k_+_1,x_k_+_2,...,x_k_+_i]-f[x_k,x_k_+_1,...,x_k_+i_-_1]}{x_k_+_i-x_k}](https://tex.z-dn.net/?f=f%5Bx_k%2Cx_k_%2B_1%2C...%2Cx_k_%2B_i%5D%3D%5Cfrac%7Bf%5Bx_k_%2B_1%2Cx_k_%2B_2%2C...%2Cx_k_%2B_i%5D-f%5Bx_k%2Cx_k_%2B_1%2C...%2Cx_k_%2Bi_-_1%5D%7D%7Bx_k_%2B_i-x_k%7D)
k∈[0,n-i]
Thus the Newton polynomial can be written as:
![P_n_-_1(x)=f[x_0]+f[x_0,x_1](x-x_0)+f[x_o,x_1,x_2](x-x_0)(x-x_1)+...+f[x_n,x_n_-_1,...,x_1](x-x_n)(x-x_n_-_1)...(x-x_1)](https://tex.z-dn.net/?f=P_n_-_1%28x%29%3Df%5Bx_0%5D%2Bf%5Bx_0%2Cx_1%5D%28x-x_0%29%2Bf%5Bx_o%2Cx_1%2Cx_2%5D%28x-x_0%29%28x-x_1%29%2B...%2Bf%5Bx_n%2Cx_n_-_1%2C...%2Cx_1%5D%28x-x_n%29%28x-x_n_-_1%29...%28x-x_1%29)
(a) I attached you the procedure in the first table, using it we have:
Operate P(x) using the distributive property:
(b) I attached you the procedure in the second table, using it we have:
Operate P(x) using the distributive property:
Answer:
1) 18
2) 144
3) 51
4) 99.6
Step-by-step explanation:
1) Multiply 1.5 by 12, as 1.5 divided by 1 is 1
2) Multiply 12 by 12, as 12 divided by 1 is 1
3) Multiply 4.25 by 12, as 4.25 divided by 1 is 1
4) Multiply 8.3 by 12, as 8.3 divided by 1 is 1
Answer: 62.6°F
This is very easy, First you have to substitute c with 17. Your equation would now be set up like this, F(17)=9/5(17)+32. (Remember PEMDAS) Multiply 17 by 9 to get 153. Next you divide 153 by 5, which will get you the answer of 30.6. Last add 32 to 30.6 and get 62.6°f, not enough to get snow but its getting chilly.
The answer is B. Because It said find the distanace between the two pont.
The distance between 10 and 8 is 2 The ditsnace between 8 and 4 is 4 The distance between 4 and 0 is 4. Add them all up 2+4+4=10
