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3 years ago

Which graph represents the inequality y>1-3x

Mathematics

1 answer:

slava [35]3 years ago

5 0

Answer:

b............ .......... which one is a b c d

For this case we must indicate the graph of the following inequality:

y≥1−3x

It is observed that inequality includes equality, so the boundary line of the graph will not be dotted, so we discard options D and C.

We test option A, we substitute the point (0,0) in the inequality, if it is fulfilled then the graph corresponds to it.

It is not fulfilled

We test the last option B, we choose the point (3,1) that belongs to the graph:

1≥1−3(3)

\1≥1−9

1≥−8

it is fulfilled

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1) A family consisting of three persons—A, B, and C—goes to a medical clinic that always has a doctor at each of stations 1, 2,

crimeas [40]

Answer:

Step-by-step explanation:

Let us record the station number 1, 2 or 3 for each family member A, B or C.

I am attaching a table containing total outcomes. Outcomes are presented along rows while the assigned station to each member is written along columns. For ease of understanding, 1 3 2 in the table should be interpreted as family member A being assigned to station 1, member B to station 3 and member C to station number 2, respectively.

From table it is clear that the total outcomes possible are 27.

We know that, probability can be defined as,

$PROBABITILY = \frac{NUMBER\;OF\;DESIRED\;OUTCOMES}{TOTAL\;NUMBER\;OF\;OUTCOMES}$

a) All Members Assigned to the Same Station.

Cases for all members being assigned to same station are as follows:

[1 1 1], [2 2 2], [3 3 3] (outcome number 1, 14 and 27 in the table).

Therefore,

$PROBABILITY\;(Case\;a) = \frac{3}{27}\\\\PROBABILITY\;(Case\;a) = 0.111$

b) At Most Two Members Assigned to the Same Station.

It means that maximum of 2 members can have the same station. Cases for this situation are as follows:

[1 1 2], [1 1 3], [1 2 1], [1 2 2], [1 3 1], [1 3 3], [2 1 1], [2 1 2], [2 2 1], [2 2 3], [2 3 2],

[2 3 3], [3 1 1], [3 1 3], [3 2 2], [3 2 3], [3 3 1], [3 3 2]

(outcome number 2, 3, 4, 5, 7, 9, 10, 11, 13, 15, 17, 18, 19, 21, 23, 24, 25 and 26 in the table).

Therefore,

$PROBABILITY\;(Case\;b) = \frac{18}{27}\\\\PROBABILITY\;(Case\;b) = 0.666$

c) All Members Assigned to a Different Station.

For this scenario, we have the following results:

[1 2 3], [1 3 2], [2 1 3], [2 3 1], [3 1 2], [3 2 1] (outcome number 6, 8, 12, 16, 20 and 22 in the table).

Therefore,

$PROBABILITY\;(Case\;c) = \frac{6}{27}\\\\PROBABILITY\;(Case\;c) = 0.222$

3 0

3 years ago

A town has 100 homes in it. According to a census, the actual distribution of pets in these homes gives a median of 0.8 pets and

stellarik [79]

The nest answer would be c> hope this helps

6 0

3 years ago

Read 2 more answers

Ariana builds wooden furniture in her wood shop. Her most popular product is an oak glider. There is a proportional relationship

sesenic [268]

10 days - 5 days = 5 days.

6 gliders - 3 gliders = 3 gliders.

They make 3 gliders in 5 days: 3/5 = 0.6 gliders per day.

y = 0.6x

The answer is A.

5 0

3 years ago

Quadrilateral KMPT is dilated by a scale factor of 3/4 to create K'M'P'T'. The perimeter of quadrilateral KMPT is x units. What

777dan777 [17]

Answer:

B) $\frac{3}{4}$ x units

Step-by-step explanation:

Let quadrilateral KMPT be a rectangle with dimensions 12 units by 8 units. Then its perimeter would be equal to:

Perimeter of a rectangle = 2 (l + b)

where: l is the length = 12 units and b is the breadth = 8 units. So that:

Perimeter of KMPT = 2 (12 + 8)

= 40 units

Dilating KMPT by a scale factor of $\frac{3}{4}$ would create K'M'P'T' of dimensions; $\frac{3}{4}$ × 12 units by $\frac{3}{4}$ × 8 units. Thus, the dimensions of K'M'P'T' would be 9 units by 6 units.

Perimeter of K'M'P'T' = 2 (l + b)

= 2(9 + 6)

= 30 units

Comparing the perimeters of KMPT and K'M'P'T', the perimeter of K'M'P'T' would be $\frac{3}{4}$ × perimeter of KMPT.

Therefore, if the perimeter of KMPT is x units, then;

perimeter of K'M'P'T' = $\frac{3}{4}$ * x units

= $\frac{3}{4}$ x units

6 0

3 years ago

P³ = 1/8 please help me if anybody can .

ivanzaharov [21]

Answer: