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3 years ago

Solve for angle..........

Mathematics

1 answer:

Hatshy [7]3 years ago

7 0

Answer:

Step-by-step explanation:

An angle formed by a tangent and secant is equal to half the difference of its intercepted arcs. ( major arc minus minor arc to be more specific. )

∠B is the angle formed by a tangent and secant

Arc CA is its intercepted arc ( minor arc to be more specific )

Arc DA is also its intercepted arc ( major arc to be more specific )

Hence, ∠B = $\frac{1}{2}$ ( Arc DA - Arc CA )

If arc CA = 51 and Arc DA = 165

Then ∠B =

$\frac{1}{2} (165-51)\\165 - 51=114\\\frac{1}{2} (114)=57$

Hence, ∠B = 57

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blagie [28]

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3 years ago

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Tju [1.3M]

B. 75

First you find the area of the triangle:

(base x height)/2
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7.5 x 10 = 75

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3 years ago

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luna ray has 1 orange pick for every 2 green picks.How manu green picks does luna have if she has 12 total picks

Bess [88]

This is how you do it!

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Now we can check that by simplifying the ratio --> 4:8 = 1:2

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Which of the following can be used to calculate the volume of water inside the fish bowl?

Lunna [17]

The volume of a sphere can be calculated as

$V=\frac{4}{3}\pi r^3$

Where r is the radius of the sphere

We want to calculate half of the volume, then we must divide that volume by 2

$V^{\prime}=\frac{1}{2}\frac{4}{3}\pi r^3$

Now we must find the radius of our sphere, the segment AB is the diameter of the sphere, and the radius is half od the diameter, then

$r=\frac{AB}{2}=\frac{12}{2}=6$

Let's put it into our equation

$\begin{gathered} V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)(\pi)(r)^3 \\ \\ V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)(\pi)(6)^3 \end{gathered}$

The problem says to use

$\pi\approx\frac{22}{7}$

Then

$V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)\left(\frac{22}{7}\right)(6)^3$

Final answer:

The formula that can be used to calculate the volume of water inside the fish bowl is

$V=\frac{1}{2}\left(\frac{4}{3}\right)\left(\frac{22}{7}\right)(6)^3$

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1 year ago