All categories

2 years ago

Solve for angle..........

Mathematics

1 answer:

Hatshy [7]2 years ago

7 0

Answer:

Step-by-step explanation:

An angle formed by a tangent and secant is equal to half the difference of its intercepted arcs. ( major arc minus minor arc to be more specific. )

∠B is the angle formed by a tangent and secant

Arc CA is its intercepted arc ( minor arc to be more specific )

Arc DA is also its intercepted arc ( major arc to be more specific )

Hence, ∠B = $\frac{1}{2}$ ( Arc DA - Arc CA )

If arc CA = 51 and Arc DA = 165

Then ∠B =

$\frac{1}{2} (165-51)\\165 - 51=114\\\frac{1}{2} (114)=57$

Hence, ∠B = 57

You might be interested in

A cheese pizza from Pizza Pie is cut into eight equal pieces. When slices are sold individually, each slice costs $1.85. Let c r

andrezito [222]

multiply the amount of one piece with the number of pieces

1.85×8=14.8

5 0

2 years ago

NEED ANSWER ASAP- FOR FINALS

irga5000 [103]

Answer:

Height: 6 feet, Length: 14 feet, Width: 35 feet.

Step-by-step explanation:

The volume of a rectangular prism is length * width * height.

We know that the height of the pool is 6 feet and that one side is 2.5 times longer than the other. It doesn't matter which side, as long it's not the height. So let's just say the width is 2.5 times bigger than the length.

That means our equation can be rewritten as V = height * length* 2.5 * length.

Plugging in what we know, we get:

$2940=(6)(l)(2.5l)\\196=l^{2} \\l=14 feet$

Now we need to find the width.

$w=2.5l\\w=2.5(14)\\w= 35feet$

6 0

2 years ago

A hollow metal sphere has 6 cm inner and 8cm outer radii. The surface charge densities on the exterior surface is +100 nC/m2 and

natulia [17]

Answer:

<h2>Outer Electric Field is 11250 N/C.</h2><h2>Inner Electric Field is -10000 N/C.</h2>

Step-by-step explanation:

First of all, we need to read carefully and analyse the problem. As you can see, is an electrical subject, and it's given surface charge densities and radius.

So, to calculate electric fields, we need to find the proper equation to do so: $E=k\frac{q}{r^{2} }$ ; as you can see, first we need to find the charges.

We can find all charges using the surface charge densities, because it has the next relation: $p=\frac{q}{A}$ ; which indicates that charge density is the amount of charge per area. But, there's a problem, we don't have areas, so we have to calculate them first with this relation: $S=4\pi r^{2}$ ; which gives us the surface of a sphere.

The inner surface: $Si=4\pi (0.06m)^{2} = 0.04 m^{2}$

The outer surface: $S=4\pi (0.08m)^{2}=0.08m^{2}$

Now we can calculate the charges,

Inner charge: $Qi=pA=(-100\frac{nC}{m^{2} } )(0.04m^{2} )=-4nC$

Outer charge: $Qo=pA=100\frac{nC}{m^{2} } )(0.08m^{2} )=8nC$

Then, we are able to calculate both fields:

Inner field: $Ei=k\frac{Qi}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{-4x10^{-9} }{0.06m^{2} }=-10000\frac{N}{C}$

Outer field: $Eo=k\frac{Qo}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{8x10^{-9} }{0.08m^{2} }=11250\frac{N}{C}$

The directions that field have is opposite each other, the inner one has an inside direction, and the outer electric field has an outside direction.

3 0

3 years ago

Solve the inequality and graph the solution set on a number line. Express the solution set in both set-builder and interval not

shusha [124]

<span>-8 < x -3 < 1
we have two inequations:
* -8<x-3 and -8+3<x-3+3 or -5 < x or x>-5
* x-3<1 or x-3+3<1+3 and we have x<4
For all cases we have -5<x<4
or </span><span>interval notations: x</span>∈(-5;4)
have fun

8 0

2 years ago

Simplify 17^2 and 18.79^2.

Westkost [7]

17^2 is 289

18.79^2 is 353.0641

7 0

3 years ago