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devlian [24]
2 years ago
7

Solve for angle..........

Mathematics
1 answer:
Hatshy [7]2 years ago
7 0

Answer:

57

Step-by-step explanation:

An angle formed by a tangent and secant is equal to half the difference of its intercepted arcs. ( major arc minus minor arc to be more specific. )

∠B is the angle formed by a tangent and secant

Arc CA is its intercepted arc ( minor arc to be more specific )

Arc DA is also its intercepted arc ( major arc to be more specific )

Hence, ∠B = \frac{1}{2} ( Arc DA - Arc CA )

If arc CA = 51 and Arc DA = 165

Then ∠B =

\frac{1}{2} (165-51)\\165 - 51=114\\\frac{1}{2} (114)=57

Hence, ∠B = 57

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2 years ago
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Answer:

Step-by-step explanation:

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Moving from left to right:

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3 years ago
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Pavlova-9 [17]

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\bf BC=\sqrt{9+16}\implies \boxed{BC=5}\\\\[-0.35em]\rule{34em}{0.25pt}\\\\C(\stackrel{x_2}{3}~,~\stackrel{y_2}{1})\qquad A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-2})\\\\\\CA=\sqrt{(-2-3)^2+(-2-1)^2}\implies CA=\sqrt{(-5)^2+(-3)^2}\\\\\\CA=\sqrt{25+9}\implies \boxed{CA=\sqrt{34}}\\\\[-0.35em]\rule{34em}{0.25pt}\\\\~\hfill \stackrel{AB+BC+CA}{\approx 18.11}~\hfill

5 0
3 years ago
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Answer:

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Step-by-step explanation:

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4 0
2 years ago
Read 2 more answers
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Answer:

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Step-by-step explanation:

= > - 3 ( 2b - 7 )

= > - 6b + 21

<h3>Hope it helps you!</h3>
6 0
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