4, 5, and 7 are mutually coprime, so you can use the Chinese remainder theorem right away.
We construct a number 
such that taking it mod 4, 5, and 7 leaves the desired remainders:
- Taken mod 4, the last two terms vanish and we have
so we multiply the first term by 3.
- Taken mod 5, the first and last terms vanish and we have
so we multiply the second term by 2.
- Taken mod 7, the first two terms vanish and we have
so we multiply the last term by 7.
Now,
By the CRT, the system of congruences has a general solution
or all integers 
, 
, the least (and positive) of which is 27.
Answer:
r=41/2
Step-by-step explanation:
You have to divide the diameter, 41, by 2 because the radius of the circle is half of the diameter. So, the answer would be 20.5
Answer:
The answer to your question is below
Step-by-step explanation:
(2x⁴ + 7x³ - 3x + 9) - (6x⁴ - 3x³ - 6x² - 17)
Step 1. take out the parenthesis, in the second term, change the signs
2x⁴ + 7x³ - 3x + 9 - 6x⁴ + 3x³ + 6x² + 17
Step 2. Group like terms
(2x⁴ - 6x⁴) + (7x³ + 3x³) + (6x²) + (-3x) + (9 + 17)
Step 3. Simplify like terms
-2x⁴ + 10x³ + 6x² - 3x + 26
16: 8/25; 38%; .41
18: 84% 43/50; 7/8; .91
20: 26.8%; 2.26; 2 2/5; 2.62; 271%
22: 21/25= 84% so yes
