How do u write 23f in verbal expression

Laurie was scuba diving. Each time she dove 5 feet deeper, she would stop and clear her ears. After Laurie had checked her instr

stepladder [879]

Answer:

Laurie's maximum depth can be represented using the expressions :

(20 × 3) = 60

(3 × 4 × 5) = 60

Step-by-step explanation:

Each depth level at which ears are checked = 5 feets

Each Depth level at which instruments are checked = 20 feets

For Laurie to check her instrument ;

Number of times ears are checked = 20/5 = 4 times

This means that for Laurie to have checked her instrument 3 times :

(4 × 3 × 5) = 60 feets

Therefore, Laurie's maximum depth can be expressed as (4 × 3 × 5) = 60 feets

4 0

2 years ago

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8th GRADE MATH

s2008m [1.1K]

The answer for the question is a

6 0

2 years ago

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What are three different ways to write 15,638 with only hundreds, tens, and ones?

saul85 [17]

Fifteen thousand six-hundred and thirty-eight

5 0

3 years ago

Determine the domain of the function h=9x/x(x^2-49)

Juliette [100K]

ANSWER

$( - \infty , - 7) \cup( - 7 , 0) \cup(0 , 7 )\cup(7 , + \infty )$

EXPLANATION

The given function is

$h(x) = \frac{9x}{x( {x}^{2} - 49) }$

This function is defined for values where the denominator is not equal to zero.

$x( {x}^{2} - 49) \ne0$

$x(x - 7)(x + 7) = 0$

The domain is

$x \ne - 7, x \ne0, \: and \: x \ne 7,$

Or

$( - \infty , - 7) \cup( - 7 , 0) \cup(0 , 7 )\cup(7 , + \infty )$

8 0

3 years ago

Two large and 1 small pumps can fill a swimming pool in 4 hours. One large and 3 small pumps can also fill the same swimming poo

kolezko [41]

Let x and y be the unit rates at which one large pump and one small pump works, respectively.

Two large/one small operate at a unit rate of

(1 pool)/(4 hours) = 0.25 pool/hour

so that

2x + y = 0.25

One large/three small operate at the same rate,

(1 pool)/(4 hours) = 0.25 pool/hour

x + 3y = 0.25

Solve for x and y. We have

y = 0.25 - 2x ==> x + 3 (0.25 - 2x) = 0.25

==> x + 0.75 - 6x = 0.25

==> 5x = 0.5

==> x = 0.1

==> y = 0.25 - 2 (0.1) = 0.25 - 0.2 = 0.05

In other words, one large pump alone can fill a 1/10 of a pool in one hour, while one small pump alone can fill 1/20 of a pool in one hour.

Now, if you have four each of the large and small pumps, they will work at a rate of

4x + 4y = 4 (0.1) + 4 (0.05) = 0.6

meaning they can fill 3/5 of a pool in one hour. If it takes time t to fill one pool, we have

(3/5 pool/hour) (t hours) = 1 pool

==> t = (1 pool) / (3/5 pool/hour) = 5/3 hours

So it would take 5/3 hours, or 100 minutes, for this arrangement of pumps to fill one pool.

6 0

3 years ago