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oksian1 [2.3K]
2 years ago
9

PEASE HELP ME 70 POINTS

Mathematics
2 answers:
scZoUnD [109]2 years ago
6 0

Answer:

x: -2

f(x): 1.5

x: 0

f(x): 0.5

x: 3

f(x): -1

Step-by-step explanation:

gayaneshka [121]2 years ago
5 0

Answer:

3/2, 1/2, - 1

Step-by-step explanation:

x + 2y = 1 --> this is 'f(x)'. Sub in the each x-value to the equations.

First part:

x = -2

x + 2y = 1

-2 + 2y = 1

2y = 3

y = 3/2

Second part:

x = 0

x + 2y = 1

0 + 2y = 1

2y = 1

y = 1/2

Third part:

x = 3

x + 2y = 1

3 + 2y = 1

2y = -2

y = -2/2

y = - 1

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Step-by-step explanation:

1854*845=1,566,630

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Question Progress<br> 10<br> Find the value of:<br> a) x² when x = 6
Delvig [45]

Answer:

x^2= 36

Step-by-step explanation:

since x = 6

therefore, x^2 = 6×6=36

3 0
2 years ago
In ΔUVW, the measure of ∠W=90°, WV = 39, UW = 80, and VU = 89. What ratio represents the cosine of ∠U?
kumpel [21]

Answer:

cos ∅ = 80/89

Step-by-step explanation:

As required from the question the picture below represent a triangle UVW . The angle W = 90°. The sides WV = 39 , VU = 89 and UW = 80. The triangle forms a right angle triangle .

Such triangle one can establish trigonometric relationship using the SOHCAHTOA principle.

The question requested us to find the ratio that represent the cosine of  ∠U.

The ∠U is represented as ∅ .

Therefore,

cos ∅ = adjacent/hypotenuse

adjacent = 80. The adjacent side is the non hypotenuse side that is next to the given angle.

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cos ∅ = 80/89

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2 years ago
Graph the following system <br> X+y=4<br> X-y=2
Lapatulllka [165]
Points that are given on x+y=4 are (0,4),(3,1) and (4,0) and points that are give for x-y=2 are (0,-2),(2,0) and (3,1)

3 0
3 years ago
Help please solve<br> <img src="https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B6x%5E5%2B11x%5E4-11x-6%7D%7B%282x%5E2-3x%2B1
Shkiper50 [21]

Answer:

\displaystyle  -\frac{1}{2} \leq x < 1

Step-by-step explanation:

<u>Inequalities</u>

They relate one or more variables with comparison operators other than the equality.

We must find the set of values for x that make the expression stand

\displaystyle \frac{6x^5+11x^4-11x-6}{(2x^2-3x+1)^2} \leq 0

The roots of numerator can be found by trial and error. The only real roots are x=1 and x=-1/2.

The roots of the denominator are easy to find since it's a second-degree polynomial: x=1, x=1/2. Hence, the given expression can be factored as

\displaystyle \frac{(x-1)(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)^2(x-\frac{1}{2})^2} \leq 0

Simplifying by x-1 and taking x=1 out of the possible solutions:

\displaystyle \frac{(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)(x-\frac{1}{2})^2} \leq 0

We need to find the values of x that make the expression less or equal to 0, i.e. negative or zero. The expressions

(6x^3+14x^2+10x+12)

is always positive and doesn't affect the result. It can be neglected. The expression

(x-\frac{1}{2})^2

can be 0 or positive. We exclude the value x=1/2 from the solution and neglect the expression as being always positive. This leads to analyze the remaining expression

\displaystyle \frac{(x+\frac{1}{2})}{(x-1)} \leq 0

For the expression to be negative, both signs must be opposite, that is

(x+\frac{1}{2})\geq 0, (x-1)

Or

(x+\frac{1}{2})\leq 0, (x-1)>0

Note we have excluded x=1 from the solution.

The first inequality gives us the solution

\displaystyle  -\frac{1}{2} \leq x < 1

The second inequality gives no solution because it's impossible to comply with both conditions.

Thus, the solution for the given inequality is

\boxed{\displaystyle  -\frac{1}{2} \leq x < 1 }

7 0
2 years ago
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