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Dmitrij [34]
3 years ago
8

Solve the compound inequality 4x – 7 > 5 or 5x + 4 ≤ –6. Question 18 options: A) –2 ≤ x 3 C) x 3

Mathematics
1 answer:
allochka39001 [22]3 years ago
8 0

Answer:

x>3 or x≤-2

Step-by-step explanation:

4x-7>5 or 5x+4≤-6

4x>5+7 or 5x≤-6-4

x>3 or x≤-2

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Step-by-step explanation:

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Factor 2m^3-12m^2+18m completely
Nina [5.8K]

Answer:

The answer is A.

Step-by-step explanation:

Firstly, you have to take out the common terms for this expression. In this expression, the common terms ard 2 and m :

2 {m}^{3}  - 12 {m}^{2}  + 18m

= 2( {m}^{3}  - 6 {m}^{2}  + 9m)

= 2m( {m}^{2}  - 6m + 9)

Next you have to factorise the brackets :

{m}^{2}  - 6m + 9

=  {m}^{2}  - 3m - 3m + 9

= m(m - 3) - 3(m - 3)

= (m - 3)(m - 3)

=  {(m - 3)}^{2}

So the final answer is :

2m {(m - 2)}^{2}

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3 years ago
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To see how costly it would be for other people to compete a similar cycling tour, you decide to work out two averages and compar
Damm [24]

Group A

Money spent by Person 1 = £500

Money spent by Person 2 = £600

Money spent by Person 3 = £900

Money spent by Person 4 = £450

Sum of money spent by group A = £2,450

Average money spent by group A = \frac{2,450}{4}

⇒ Average money spent by group A = £612.5

Group B

Money spent by Person 1 = £700

Money spent by Person 2 = £500

Money spent by Person 3 = £680

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Sum of money spent by group B = £2,380

Average money spent by group B = \frac{2,380}{4}

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Hence, Group B had lower average spend.

4 0
3 years ago
The radioactive element​ carbon-14 has a​ half-life of 5750 years. A scientist determined that the bones from a mastodon had los
Gnesinka [82]

The bones at the time they were​ discovered when the radioactive element​ carbon-14 has a​ half-life of total 5750 years are 10062.5-year-old.

<h3>What is half-lives?</h3>

Half lives is the time interval which is need to decay the atomic nuclei of a radioactive sample.

There is a scientist who determined that the bones from a mastodon had lost 70.3​% of their​ carbon-14.  Thus, the fraction remaining is,

f=1-(70.3/100)=1-0.703

f=1-(70.3/100)=0.297

Now the fraction remaining can be given as,

f=(1/2)ⁿ

Here, n is the half life elapsed. Put the value of fraction remaining.

0.297=(1/2)ⁿ

n=1.75

The radioactive element​ carbon-14 has a​ half-life of total 5750 years. Thus,

Years=1.75*5750

Years=10062.5

Thus, the bones at the time they were​ discovered when the radioactive element​ carbon-14 has a​ half-life of total 5750 years are 10062.5-year-old.

Learn more about the half lives here;

brainly.com/question/2320811

#SPJ1

6 0
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