All categories

3 years ago

Please tell me if it 1 2 3 4 or 5

Mathematics

1 answer:

Gnesinka [82]3 years ago

3 0

I would say
B)
the correct inequality begins with y<....
and C)
the graph has a dotted line

You might be interested in

Evaluate f (2) if f (x)= 10-x^3

weeeeeb [17]

<span> f (x)= 10-x³.
f(2) means the value of the function when x=2.
So, we need to substitute 2 instead of x.

f(2) = 10 - 2³ = 10-8 =2

f(2) = 2

</span>

7 0

4 years ago

I'll give u a kith pls help

lord [1]

ANSWER:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form:

(−2,−16)

Equation Form:

x= −2, y= −16

8 0

3 years ago

Read 2 more answers

What is the exact solution to the equation 4^5x=3^(x-2)<br> list the steps to get the answer

scoray [572]

Answer: x = -0.377

Step-by-step explanation:

We have the equation:

4^(5*x) = 3^(x - 2)

Now we can use the fact that:

Ln(A^x) = x*Ln(A)

Then we can apply Ln(.) to both sides of the equation to get:

Ln(4^(5*x)) = Ln(3^(x - 2))

(5*x)*Ln(4) = (x - 2)*Ln(3)

(5*x)*Ln(4) - x*Ln(3) = -2*Ln(3)

x*(5*Ln(4) - Ln(3)) = -2*Ln(3)

x = -2*Ln(3)/(5*Ln(4) - Ln(3)) = -0.377

6 0

3 years ago

The mean rent of a 3-bedroom apartment in Orlando is $1300. You randomly select 10 apartments around town. The rents are normall

lana [24]

Answer:

96.49% probability that the mean rent is more than $1100

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .