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3 years ago

10

Can someone help me with this problem thanks!

1 answer:

ki77a [65]3 years ago

6 0

Answer:

Bbbbbbbbbbbbbbbbbbbbbbb

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Find the value of x for this trapezoid.

Lisa [10]

You just add up all of the sides to find the x

4 0

3 years ago

Veronda has a bag of mixed shapes. She chooses 3 shapes and fits them together to form a figure as shown. 8 cm 4 cm K 17 cm What

Ainat [17]

The area of the figure created by Verona is 96.56 cm²

<h3>Area</h3>

Area is the amount of space occupied by a two dimensional object.

The area of the circle = (1/4) * π * 4² = 12.56 cm²

The area of the square = 8 cm * 8 cm = 64 cm²

Area of the triangle = (1/2) * 8 cm * (17 - 8 - 4) = 20 cm²

Area of the figure created by Verona = 12.56 + 64 + 20 = 96.56 cm²

The area of the figure created by Verona is 96.56 cm²

Find out more on area at: brainly.com/question/25292087

7 0

2 years ago

The length of a rectangle is 5 inches more than twice a number.The width is 4 inches less than the same number.If the area of th

umka2103 [35]

Answer:

n = 5, n = -7/2

Step-by-step explanation:

2n + 5 = l

n - 4 = w

A = l × w = 15

(2n + 5)(n-4) = 15

2n^2 - 8n + 5n - 20 = 15

2n^2 -3n - 35 = 0

(2n + 7)(n - 5) = 0

2n + 7 = 0 or n - 5 = 0

n = -7/2 or n = 5

6 0

3 years ago

Please solve i will give brainiest 100 point question ****** do the whole page please need to pass or i will fail its my final t

dmitriy555 [2]

Answer:

1. Find the difference between the areas.

<u>Area of the small rectangle</u>: $(x+2)(x+7)=x^2+7x+2x+14=x^2+9x+14$

<u>Area of the big rectangle</u>: $(x+9)(x+11)=x^2+11x+9x+99=x^2+20x+99$

The difference is: $11x+85$

$( x^2+20x+99)- (x^2+9x+14)=x^2+20x+99-x^2-9x-14=11x+85$

2.

You can solve this question just by looking at the graph.

a) The height is 4 meters.

$f(d)=h=-2d^2+7d+4$

To find the height of the bleachers, we should consider the moment before the shoot, when the distance is equal to 0.

$f(0)=h=-2(0)^2+7(0)+4$

$h=4$

The height is 4 meters.

b) 9 meters.

For $d=1$

$f(1)=h=-2(1)^2+7(1)+4$

$f(1)=h=-2+7+4$

$h=9$

b) The ball travels 4 meters.

But to calculate it, it is when $h=0$

$0=-2d^2+7d+4$

Using the quadratic formula:

$d=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$d=\frac{-7 \pm \sqrt{7^2-4\left(-2\right)4}}{2\left(-2\right)}$

$d=\frac{-7\pm\sqrt{81}}{-4}$

$d=\frac{-7\pm9}{-4}$

It will give us to solutions, once it is a quadratic equation, but we are talking about a positive distance.

$d=-\frac{1}{2} \text{ or }d=4$

3.

In this question, we have to find the area of the cylinder and the sphere.

From the information given, we have

a = 5mm and d = 5mm, therefore the radius is 2.5 mm.

The volume of a cylinder:

$V=\pi r^2h$

$V=\pi (2.5)^2 \cdot 5$

$V=31.25 \pi$

$V_{c} \approx 98.17 \text{ m}^3$

The volume of the sphere:

$V=\frac{4}{3} \pi r^2$

$V_{s} \approx 65.4 \text{ m}^3$

The volume of the capsule is approximately $163.57 \text{ m}^3$

3 0

4 years ago

Teri ran 8 kilometers. One mile is approximately equal to 1.6 kilometers. Which measurement is closest to the number of miles Te

balandron [24]

Answer:

12.8

Step-by-step explanation:

8 x 1.6 = 12.8

That should be the answer

6 0

3 years ago

Read 2 more answers