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Gre4nikov [31]
3 years ago
5

Solve y=x2-5 for x.

Mathematics
1 answer:
faltersainse [42]3 years ago
7 0
Answer: x=+/- square root of y+5 (A, i think this one kinda confused me)

y=x^2-5
substitute y for 0
0=x^2-5
subtract x^2 on both sides
-x^2=-5
since they both can be negative and positive change signs to positive to be easier
x^2=5
square root both sides
x=+/- square root of 5
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What is the equation of this line in slope-intercept form?
12345 [234]

Answer:

y = -2x + 5

Step-by-step explanation:

Slope-intercept form: y = mx + b

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7 0
2 years ago
Simplify and Evaluate
zalisa [80]
\dfrac{2^{-1} + 5^{-1}}{10^{-1} - 5^{-2}} =

= \dfrac{\frac{1}{2} + \frac{1}{5}}{\frac{1}{10} - \frac{1}{5^2}}

=\dfrac{\frac{1}{2} + \frac{1}{5}}{\frac{1}{10} - \frac{1}{25}}

=\dfrac{\frac{5}{10} + \frac{2}{10}}{\frac{5}{50} - \frac{2}{50}}

=\dfrac{\frac{7}{10}}{\frac{3}{50}}

= \frac{7}{10} \times \frac{50}{3}

= \frac{7}{1} \times \frac{5}{3}

= \frac{35}{3}


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3 years ago
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