Solve for x -3 < 3x -9 < 9

Mathematics

1 answer:

bezimeni [28]3 years ago

5 0

Answer:

2 < x < 6

Step-by-step explanation:

- 3 < 3x - 9 < 9 ( add 9 to each interval )

6 < 3x < 18 ( divide each interval by 3 )

2 < x < 6

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A triangle's area is given by the expression 3x2-x+12. The height is 6x. The base off the triangle is the quotient of the area a

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You have known the formula Length of base is la division of Area and a haft of the height.
So we have 3
$(3 {x}^{2} - x + 12) \div ( \frac{1}{2} \times 6x)$
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$(3 {x}^{2} - x + 12) \div 3x$
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nevsk [136]

Let C be the center of the circle. The measure of arc VSU is $2+114x$ , so the measure of the minor arc VU is $360-(2+114x)=358-114x$ . The central angle VCU also has measure $358-114x$ .

Triangle CUV is isosceles, so the angles CVU and CUV are congruent. The interior angles of any triangle are supplementary (they add to 180 degrees) so

$m\angle VCU+2m\angle CUV=180$