The equivalent expression is
.
We have the following expression -

We have to find its equivalent value.
<h3>What is the equivalent expression of the following expression-</h3>

In order to divide two exponents with same base, we use the 'Quotient property of exponents.
The equivalent expression can be written as -
f(x, y) = 
In the question given we have -
Using the property discussed above -
=
= 
Hence, the equivalent expression is
.
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Answer:
The root is x = -2
Step-by-step explanation:
1. Add 4 on both sides.
x^2 + 4r + 4 = 0
2. What two numbers, if added together and multiplied together, give 4?
2 and 2.
3. Factor
(x+2)(x+2)=0
4. Solve
x = -2 (There is only one root for this quadratic equation.)
Please give me brainliest is this is right. Than you!
Answer:
simplified answer is: -x-15/6
evaluated answer is; -(x-15/6)
Step-by-step explanation: if correct brainliest plz
if wrong i am sorry
Step-by-step explanation:
If two quantities x and y vary (change) together in such a manner that the ratio of their corresponding values remains constant, then x and y are said to be in direct proportion.
The two cars will be 5.5 miles apart after 5.5 hours.
Step-by-step explanation:
Given,
Speed of first car = 57 mph
Time = 5.5 hours
Distance covered by first car = Speed * Time
Distance covered by first car = 57*5.5 = 313.5 miles
Speed of other car = 58 mph
Distance covered by other car = 58*5.5 = 319 miles
Difference = 319 - 313.5
Difference = 5.5 miles
The two cars will be 5.5 miles apart after 5.5 hours.
Keywords: speed, distance
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