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Olin [163]
3 years ago
12

Which of the following sets of ordered pairs is a function

Mathematics
2 answers:
zaharov [31]3 years ago
8 0

Answer:

Where’s the work to it

Step-by-step explanation:

N76 [4]3 years ago
5 0

Answer:

Example:A {(1,5}),(2,6),(4,5)}    B/ {(5,5),(6,5),(5,6)} C/ {(2,3),(-4,5),(2,5)}/ D/ {(2,3),(2,6),(-2,8)}

Step-by-step explanation:

Ordered pairs is a function that is the question , every ordered pair has their input and output .

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A party supply store is selling balloons for $6 per dozen. What is the price per balloon? $​
Tcecarenko [31]

Answer:

2 per balloon

Step-by-step explanation:

Dozen = 12

6 0
2 years ago
Read 2 more answers
HELP ASAP <br><br> What is the value of x?<br> O x = 55°<br> O x = 60°<br> O x = 70°<br> O x = 110°
valina [46]

Answer:

the answer is the answer the answer is x=55 degrees because the angle sum for a triangle is 180 degrees and because we are told angle A and angle C are congruent that means you can simply take 180 - 70 to get 110 and i simply divided that by 2 and got 55 degrees

Step-by-step explanation:

5 0
3 years ago
CAN SOMEBODY HELP WITH THIS QUESTION ASAP​
tia_tia [17]

Answer:

The rectangles are not similar

Step-by-step explanation:

In order to check whether they are similar, we need to take the ratio of their similar sides and ensure they are equal to a constant k.

Hence;

AB/PL = AD/LM = k

32/26 = 18/12 = k

16/13 = 9/6 = k

Since the scale factor is not the same, hence the rectangles are not the same.

6 0
3 years ago
Solve for XX. Assume XX is a 2×22×2 matrix and II denotes the 2×22×2 identity matrix. Do not use decimal numbers in your answer.
sveticcg [70]

The question is incomplete. The complete question is as follows:

Solve for X. Assume X is a 2x2 matrix and I denotes the 2x2 identity matrix. Do not use decimal numbers in your answer. If there are fractions, leave them unevaluated.

\left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]· X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right] =<em>I</em>.

First, we have to identify the matrix <em>I. </em>As it was said, the matrix is the identiy matrix, which means

<em>I</em> = \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

So, \left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]· X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right] =  \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

Isolating the X, we have

X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]= \left[\begin{array}{cc}2&8\\-6&-9\end{array}\right] -  \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

Resolving:

X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]= \left[\begin{array}{ccc}2-1&8-0\\-6-0&-9-1\end{array}\right]

X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]=\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]

Now, we have a problem similar to A.X=B. To solve it and because we don't divide matrices, we do X=A⁻¹·B. In this case,

X=\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]⁻¹·\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]

Now, a matrix with index -1 is called Inverse Matrix and is calculated as: A . A⁻¹ = I.

So,

\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]·\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]=\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

9a - 3b = 1

7a - 6b = 0

9c - 3d = 0

7c - 6d = 1

Resolving these equations, we have a=\frac{2}{11}; b=\frac{7}{33}; c=\frac{-1}{11} and d=\frac{-3}{11}. Substituting:

X= \left[\begin{array}{ccc}\frac{2}{11} &\frac{-1}{11} \\\frac{7}{33}&\frac{-3}{11}  \end{array}\right]·\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]

Multiplying the matrices, we have

X=\left[\begin{array}{ccc}\frac{8}{11} &\frac{26}{11} \\\frac{39}{11}&\frac{198}{11}  \end{array}\right]

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3 years ago
HELP ASAP!!!!!!!!!!!!!! ITS AN EMERGENCY!!!!!!!!
laila [671]

Answer

Step-by-step explanation:

4 0
2 years ago
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