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Olin [163]
3 years ago
12

Which of the following sets of ordered pairs is a function

Mathematics
2 answers:
zaharov [31]3 years ago
8 0

Answer:

Where’s the work to it

Step-by-step explanation:

N76 [4]3 years ago
5 0

Answer:

Example:A {(1,5}),(2,6),(4,5)}    B/ {(5,5),(6,5),(5,6)} C/ {(2,3),(-4,5),(2,5)}/ D/ {(2,3),(2,6),(-2,8)}

Step-by-step explanation:

Ordered pairs is a function that is the question , every ordered pair has their input and output .

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Gnom [1K]
Im in fifth grade too. that was on my homework it confused me so much
8 0
3 years ago
Giselle works as a carpenter and as a blacksmith.
Usimov [2.4K]

Answer:

34.5 hours as carpenter or 27.6 hours for blacksmith (Not sure about this sorry)

Step-by-step explanation:

690 ÷ 20 and 690 ÷ 25

8 0
3 years ago
1 of 6 The length of each side of a square is 6.1 cm rounded to 1 decimal place. Write the error interval for the perimeter, p ,
arsen [322]

The error interval of the perimeter is 6.1 cm ≤ p < 6.15 cm

<h3>How to determine the error of interval?</h3>

The perimeter is given as:

P = 6.1 cm to 1 decimal place

The smallest number that can be approximated to 6.1 is 6.05, while the largest number is less than 6.15

This means that the interval is:

6.1 cm ≤ p < 6.15

Read more about error interval at:

brainly.com/question/16810055

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8 0
2 years ago
Please help??! Solve by elemination <br>4x + y = 6<br>12x + 3y = 18<br>Show your work
RUDIKE [14]
Multiply -3[4x+y=6].
This gets you -12x-3y=-18.
Add the two equations together to eliminate the y.
-12x - 3y = -18
+ 12x + 3y = 18
------------------------
0 = 0
This means that these are in fact the same line, therefore there are infinite solutions.
8 0
3 years ago
For a population with µ = 80 and σ = 20, the Sampling distribution of the Mean, based on n = 16 will have an expected value of t
allsm [11]

Answer:

Will have an expected value of the mean = 80 and a standard error of the mean = 5

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 80, \sigma = 20

n = 16

So the mean is 80 and the standard deviation is s = \frac{20}{\sqrt{16}} = 5

Will have an expected value of the mean = 80 and a standard error of the mean = 5

6 0
3 years ago
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