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3 years ago

Find the distance between the two points rounding to the nearest 10th! PLS HELP ASAP!!!!

Mathematics

2 answers:

Papessa [141]3 years ago

7 0

Answer:

8.5

Step-by-step explanation:

we can plug those coordinates into the distance formula

d = √(x2 - x1)2 + (y2 - y1)2

d= √((-7)-(-1)^2+((-1)-(5)^2

d = √36+36

d=√72 = 8.48 or 8.5

My name is Ann [436]3 years ago

4 0

Answer:

8.5

Step-by-step explanation:

d = √[(-7+1)²+(-1-5)²]

= √[(-6)²+(-6)²]

=√(36+36)

=√72

= 8.5

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3 years ago

Is 7/8 or 11/10 closer to 1? How did you decide anybody help please?

erik [133]

Let

A-----> $\frac{7}{8}$

B-----> $\frac{11}{10}$

C-----> $1$

we know that

Point A-------> Multiply numerator and denominator by $10$

$\frac{7*10}{8*10} =\frac{70}{80}$

Point B-------> Multiply numerator and denominator by $8$

$\frac{11*8}{10*8} =\frac{88}{80}$

Point C-------> Multiply numerator and denominator by $80$

$\frac{1*80}{1*80} =\frac{80}{80}$

Find the distance Point A to Point C

$\frac{80}{80} -\frac{70}{80} =\frac{10}{80}$

Find the distance Point B to Point C

$\frac{88}{80} -\frac{80}{80} =\frac{8}{80}$

therefore

$\frac{8}{80} < \frac{10}{80}$

Point B is closer to Point C

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$\frac{11}{10}$ is closer to $1$

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