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2 years ago

Is this the right answer?

Mathematics

1 answer:

Aliun [14]2 years ago

5 0

Answer:

yep the Answer is right

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Make b the subject of the formula <br><img src="https://tex.z-dn.net/?f=k%20%3D%20%20%5Cfrac%7Bbrt%7D%7Bv%20-%20b%7D%20" id="Tex

balu736 [363]

Answer:

b = $\frac{kv}{k+rt}$

Step-by-step explanation:

Given

k = $\frac{brt}{v-b}$ ← multiply both sides by (v - b)

k(v - b) = brt ← distribute left side

kv - kb = brt ( subtract brt from both sides )

kv - kb - brt = 0 ( subtract kv from both sides )

- kb - brt = - kv ( multiply through by - 1 to clear the negatives )

kb + brt = kv ← factor out b from each term on the left

b(k + rt ) = kv ← divide both sides by (k + rt )

b = $\frac{kv}{k+rt}$

5 0

2 years ago

An athlete trains for 95 min each day for as many days as possible. Write an equation that relates the number of days d that the

Mashcka [7]

The athlete trains for 95 min for 1 day

In 380 min he/she trains for 380 × 1/95 = 4days

7 0

2 years ago

HELP 1/7z+2=-6/7z what’s the solution set please send help I’m suffocating under homework

Snezhnost [94]

Isolate the z. Note the equal sign. Subtract 1/7z to both sides

1/7z (-1/7z) + 2 = -6/7z (-1/7z)

2 = -6/7z - 1/7z

Simplify. Combine like terms

2 = -7/7z

2 = -1z

Isolate the z. Divide -1 from both sides

(2)/-1 = (-1z)/-1

z = 2/-1

z = -2

-2 is your answer

hope this helps

8 0

2 years ago

Write a multiplication expression that can be used to solve 2/3a = 30.

Tresset [83]

<h3>Answer:</h3>

a=45

<h3>Solution:</h3>

We need to multiply both sides by 3 in order to get rid of the denominator, 3:
2/3a•3=30•3
2a=90
Divide both sides by 2:
a=45

Hope it helps.

Do comment if you have any query.

8 0

1 year ago

Find the equations of the tangents to the curve y = x²-x-12 at each of the points where the curve crosses the x-axis.

poizon [28]

Step-by-step explanation:

First, find the zeroes of the parabola

${x}^{2} - x - 12$

${x}^{2} - 4x + 3x - 12$

$x(x - 4) + 3(x - 4)$

$(x + 3)(x - 4) = 0$

$x = - 3$

$x - 4 = 0$

$x = 4$

So the zeroes or where the curve crosses the x axis is at 4 and -3.

Now, we take the derivative of the function.

$\frac{d}{dx} ( {x}^{2} - x - 12) = 2x - 1$

Plug in -3, and 4 into the derivative function

$2( - 3) = - 7$

$2(4) - 1 = 7$

So at x=-3, our slope of the tangent line is -7 and must pass through (-3,0). So we use point slope formula.

$y - y _{1} = m(x - x _{1})$

$y - 0 = - 7(x - ( - 3)$

$y = - 7x - 21$

At x=4, our slope of tangent line is 7, and pass through (4,0) so

$y - 0 = 7(x - 4)$

$y = 7x - 28$

So the equations of tangent is

$y = - 7x - 21$

$y = 7x - 28$

6 0

2 years ago