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Alina [70]
3 years ago
6

Can someone help me please

Mathematics
2 answers:
11111nata11111 [884]3 years ago
7 0

Answer:

y=42

Step-by-step explanation:

7y = 6×49

y = (6×49)÷7

y= 42

gavmur [86]3 years ago
6 0

hope it will be right

donot know just try

after knowing right answer, teel me is this how i do is right or wrong

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The Sanchez family is planning a party. They want to budget spending $25 per guest. They already spent $200 on supplies and will
OverLord2011 [107]

Answer:

4

Step-by-step explanation:

20×25 = 500

20 guest

25 dollars per guest

75s+200= 500

75s = 300

S = 4

They can afford to buy 4 cases of snacks and stay within their budget.

3 0
2 years ago
Find the unknown side of the triangle. Urgent
kramer

Answer:

13 in

Step-by-step explanation:

It’s a right triangle, so use the Pythagorean Theorem.

12²+5²=c²

144+25=c²

169=c²

√169=c

13=c

4 0
3 years ago
Solve the system of equations below. Enter your answer in the boxes.
Vesna [10]
Simplifying
8a + 12b = 92

Solving
8a + 12b = 92

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-12b' to each side of the equation.
8a + 12b + -12b = 92 + -12b

Combine like terms: 12b + -12b = 0
8a + 0 = 92 + -12b
8a = 92 + -12b

Divide each side by '8'.
a = 11.5 + -1.5b

Simplifying
a = 11.5 + -1.5b
3 0
2 years ago
Find (f −1)'(a).<br><br> f(x) = 4 + x2 + tan(πx/2), −1 &lt; x &lt; 1, a = 4
Vinvika [58]

Answer:

The  solution  is   (f^{-1})'(a) = \frac{2}{\pi }

Step-by-step explanation:

From the question we are told that

      The  function is  f(x) =  4 +  x^2  + tan [\frac{ \pi x}{2} ] ,     -1 <  x  <  1  a =  4

Here we are told find  (f^{-1}) (a)

Let equate

     f(x) =  a

So  

      4 +  x^2  + tan[\frac{\pi x }{2} ] =  4

       x^2  + tan[\frac{\pi x }{2} ]  =  0

For the equation above to be valid x must be equal to 0

  Now when x = 0

       f(0) = 4+0^2 + tan [\frac{ \pi * 0}{2} ]

=>      f(0) =  4

=>  0 =  f^{-1} (4)

Differentiating  f(x)

     f(x)'  =  0 + 2x  + sec^2 (\frac{\pi x}{2} )\cdot \frac{\pi}{2}

Now

    since 0 =  f^{-1} (4)

We have

      f(0)'  =  0 +  \frac{\pi }{2}  sec^2 (0)

       f(0)'  = \frac{\pi }{2}

Now  

        (f^{-1})'(a) =  \frac{1}{(\frac{\pi}{2} )}

        (f^{-1})'(a) = \frac{2}{\pi }

       

3 0
3 years ago
What is the product? 6(x^2-1) 6x-1/6(x+1)
arsen [322]

Answer:

Step-by-step explanation:

Step 1: 6(x^2-1) [(6x-1)/(6(x+1)]

Step 2:  [6(X+1) (X-1) (6X-1)] / 6(X+1)

Explanation: Factor out the (x^2-1)

Step 3: (6X-1) (X-1)

Explanation: Cancel out common terms on the top and the bottom of the fraction.

Step 4: 6X^2 - 6X-X+1

Explanation: Multiply out and Simplify

Answer: 6X^2 - 7x+1

6 0
3 years ago
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