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3 years ago

11

Lily buys a sweater that is on sale for $42, which is 75% of the original price of the sweater. What was the original price of t

he sweater?

1 answer:

denpristay [2]3 years ago

5 0

25% is 14 so 100% is 56

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Pleeeeeeeeeeeeeeeeeeeeeeeeeeeeease help meeeeeeeeeeeeee

klio [65]

Answer:

<h2><u>V≈56.55 mm^3</u></h2>

Step-by-step explanation:

I used the formula

V=πr^2h

Hope this helps! (brainliest pls?)

6 0

3 years ago

Shannon wants to find out about paying taxes this year. She visits www.mikestaxadvice.com. This information is -

Anna007 [38]

Unrealiable

If she wants to know how to pay taxes she should visit the governments webiste. This is a third party website and could give her unreliable infortmation, she should be checking with the governments website.

7 0

3 years ago

Read 2 more answers

What is the base (in inches) of a triangle with an area of 161 square inches and a height of 14 inches?

pantera1 [17]

$\textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh ~~ \begin{cases} b=base\\ h=height\\[-0.5em] \hrulefill\\ h=14\\ A=161 \end{cases}\implies 161=\cfrac{1}{2}b(14) \\\\\\ 161=7b\implies \cfrac{161}{7}=b\implies 23=b$

7 0

2 years ago

In the system of equations, r and s are constants. If the system has infinitely many solutions, what is the value of rs?

exis [7]

Answer: B) -48

Step-by-step explanation:

If the system of two linear equations $a_1x+b_1y=c_1\ \&\ a_2+b_2y=c_2$ has infinitely many solutions , then

$\dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}=\dfrac{c_1}{c_2}=k$

For the given system of linear equations : $rx-sy=26\\4x+3y=13$

We , will have

$\dfrac{r}{4}=\dfrac{-s}{3}=\dfrac{26}{13}=2\\\\\Rightarrow\ r= 4\times2=8\ \ \&\ \ s=2\times-3=-6$

The value of $rs=(8)\times-6=-48$

Hence, the value of rs is -48.

Thus , the correct option is B) -48.

6 0

3 years ago

Are the functions f(x) = (x^2-1)/(x-1) and g(x)= x+1 equal for all x?

Vinvika [58]

$\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-------------------------------\\\\$

$\bf f(x)=\cfrac{x^2-1}{x-1}\implies f(x)=\cfrac{x^2-1^2}{x-1}\implies f(x)=\cfrac{(\underline{x-1})(x+1)}{\underline{x-1}}
\\\\\\
f(x)=x+1\qquad \qquad \qquad \qquad \qquad g(x)=x+1\\\\
-------------------------------\\\\
\textit{they're, kinda, except that, when x = 1}
\\\\\\
g(x)=(1)+1\implies g(x)=2
\\\\\\
f(x)=\cfrac{(1)^2-1}{(1)-1}\implies f(x)=\cfrac{0}{0}\impliedby und efined$

7 0

3 years ago