This is an interesting question. I chose to tackle it using the Law of Cosines.
AC² = AB² + BC² - 2·AB·BC·cos(B)
AM² = AB² + MB² - 2·AB·MB·cos(B)
Subtracting twice the second equation from the first, we have
AC² - 2·AM² = -AB² + BC² - 2·MB²
We know that MB = BC/2. When we substitute the given information, we have
8² - 2·3² = -4² + BC² - BC²/2
124 = BC² . . . . . . . . . . . . . . . . . . add 16, multiply by 2
2√31 = BC ≈ 11.1355
Assign variables to you unknowns.
c = $ cars
t = $ trucks
6c + 3t = 4800
8c + t = 4600
use substitution or elimination to solve the system of equations.
using elimination.. multiply second equation by -3 and add to the other to combine equations into one.
6c + 3t = 4800
-3(8c + t = 4600)
---------------------------
-18c + 0 = -9000
c = 9000/18
c = 500 $
use this in one of the equations to find the cost of a truck.
8(500) + t = 4600
4000 + t = 4600
t = 4600 - 4000
t = 600 $
question asks
2(500) + 3(600) =
1000 + 1800 = 2800 $
Answer:
Answer:
21378.6
Step-by-step explanation:
You move the decimal point four places towards the right.
Answer:
The fourth term is -102----------------------------------------------
Explanation:
The term after the nth term is generated by this rule
which means that we first
Step 1) multiply the nth term (
) by -4
Step 2) Add the result of step 1 to the value 2 to get the next term in the sequence
Let's follow those steps above to generate the first four terms
The first term is
. In short, the first term is 2
The second term is...
So the second term is -6
The third term is...
The third term is 26
Finally, the fourth term is...
The fourth term is -102.
<span>11÷12</span><span> can be written as eleventh twelves
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